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2 years ago

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How so different biogeographical zones affect agricultural practice?

1 answer:

GrogVix [38]2 years ago

5 0

Answer:

Biodiversity within a given ecosystem will be affected by a number of biogeographic factors: Larger habitats tend to promote biodiversity better than smaller habitats (more available niches = less competition) Ecology at the edges of ecosystems is different from central areas (e.g. more sunlight, more wind,

hope it helps

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In a cross between two strains that are true breeding for purple and white flowers, the F2 phenotypic ration would be 1/4 purple

velikii [3]

Answer:

Only if one of individual has incomplete dominance.

Explanation:

Using a Punnet square, only if one individual has incomplete dominance could have this ration. Otherwise, if the 2 individuals had a homozygous phenotype, whit one individual for dominant and the other for recessive, the ratio would be all purple.

7 0

3 years ago

A man is suffering from aids then write any two ways in whicg he could have got this disease.

bonufazy [111]

Answer:

HIV is the correct answer

8 0

3 years ago

Assume that the red blood cell counts of women are normally distributed with a mean of 4.577 million cells per microliter and a

postnew [5]

Answer: C. 82.26%

Explanation:

Given : The red blood cell counts of women are normally distributed with

$\mu=4.577\text{ million cells per microliter}$

$\sigma=0.382\text{ million cells per microliter}$

Let X be the random variable that represents the red blood cell counts of randomly selected woman.

Z-score : $z=\dfrac{X-\mu}{\sigma}$

For X=4.2

$z=\dfrac{4.2-4.577}{0.382}\approx-0.99$

For X=5.4

$z=\dfrac{5.4-4.577}{0.382}\approx2.1544$

Now, the probability that the women have red blood cell counts in the normal range from 4.2 to 5.4 million cells per microliter will be :-

$P(4.2$

Hence, 82.26% of women have red blood cell counts in the normal range from 4.2 to 5.4 million cells per microliter.

4 0

3 years ago

g Indium has two naturally occurring isotopes: 113In with an atomic weight of 112.904 amu, and 115In with an atomic weight of 11

aleksandrvk [35]

Answer:

Fraction-of-occurrences of 115In isotope $= 0.957$

Explanation:

As we know weight of 113 In isotope is equal to the sum of product of fraction-of-occurrences of two constituents isotopes and their atomic weight

$^{115}In_w = f_{113}*A_{113} + f_{115}*A_{115}$ ------(1)

As we know sum of fraction-of-occurrences of two constituents isotopes is equal to one.

$f_{113} + f_{115} = 1\\f_{113} = 1- f_{115}$ ---------(2)

Substituting the given values in equation 1, we get

$^{115}In_w = f_{113}*A_{113} + f_{115}*A_{115}\\114.818 = (1 - f_{115}) * 112.904 + f_{115} * 114.904\\f_{115} = 0.957$

Substituting this value in equation 2 we get -

$f_{113} = 1- f_{115}\\f_{113} = 1- 0.957 \\f_{113} = 0.043$

7 0

3 years ago

The number of species living within hand ecosystem is its

MakcuM [25]

Answer: no idea if its true aka my answer

Explanation: a measure of its biodiversity.

5 0

1 year ago