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Flauer [41]
2 years ago
10

Help me pls lol I don’t understand

Mathematics
2 answers:
Leona [35]2 years ago
7 0
J = (5,6)
K = (5,1)
L = (10,2)
Fed [463]2 years ago
7 0

J'= (-5,-6)

K'=(-5,-1)

L'=(-10,-2)

See graph below.

Hope this helps! Have a good day! :)

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The PTA makes a $5.00 profit on each school sweatshirt they sell. If they made a
Scilla [17]

Answer:

434 sweatshirts were sold

Step-by-step explanation:

$2,170/$5 = 434

7 0
2 years ago
Una persona asegura que su casa tiene forma rectangular y que el perímetro de la misma es de 18 m y que además, su área es de 21
leva [86]

Considerando las fórmulas para el perímetro y el área de un rectángulo, hay que se chega en una <u>eccuación cuadrática sin solución</u>, o sea, las medidas no son posibles y la persona estaba mintiendo.

<h3>¿Cuál es la fórmula para el perímetro y el área de un rectángulo?</h3>

Considerando que las dimensiones son l y w, hay que:

  • El perímetro es: P = 2(l + w).
  • El área es: A = lw.

El <u>perímetro es de 18 m</u>, o sea:

2(l + w) = 18

l + w = 9

l = 9- w.

El <u>área es de 21 m²</u>, o sea:

lw = 21

(9- w)w = 21

-w² + 9 - 21 = 0

w² - 9w + 21 = 0

El discriminante es dado por:

D = 9² - 4 x 1 x 21 = -3.

El discriminante negativo implica que la <u>eccuación cuadrática no tiene solución</u>, o sea, las medidas no son posibles y la persona estaba mintiendo.

Puede-se aprender más a cerca de el perímetro y el área de un rectángulo en brainly.com/question/26475963

#SPJ1

4 0
1 year ago
Titus had 1/2 can of paint. He used 2/3 to paint a tabletop. What fraction of a full can of paint did Titus use?
dimaraw [331]
I think its 1 1/6 idk
7 0
3 years ago
Initial Knowledge Check
Cloud [144]

Answer:

I believe it would be five dollars since if you divide the price with the percentage yknow

5 0
3 years ago
Is there any systematic tendency for part-time college faculty to hold their students to different standards than do full-time f
alexandr1967 [171]

Answer:

H0 : μ1 - μ2 = 0

H1 : μ1 - μ2 ≠ 0

-1. 34

0.1837

Step-by-step explanation:

Full time :

n1 = 125

x1 = 2.7386

s1 = 0.65342

Part time :

n2 = 88

x2 = 2.8439

s2 = 0.49241

H0 : μ1 - μ2 = 0

H1 : μ1 - μ2 ≠ 0

Test statistic :

The test statistic :

(x1 - x2) / sqrt[(s1²/n1 + s2²/n2)]

(2.7386 - 2.8439) / sqrt[(0.65342²/125 + 0.49241²/88)]

−0.1053 / sqrt(0.0034156615712 + 0.0027553)

-0.1053 /0.0785554

= - 1.34

Test statistic = - 1.34

The Pvalue :

Using df = smaller n - 1 = 88 - 1 = 87

Pvalue from test statistic score ;

Pvalue = 0.1837

Pvalue > α ; We fail to reject the null and conclude that the GPA does not differ.

At α = 0.01 ; the result is insignificant

6 0
2 years ago
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