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olasank [31]
1 year ago
5

Find the Surface Area of the prism please

Mathematics
1 answer:
Sergeeva-Olga [200]1 year ago
8 0

Answer:

<h2>1544 m³</h2>

Step-by-step explanation:

surface area = 2 × base + lateral area

 base = (10×20)÷2 = 100

 Lateral area = perimeter × height

                      = (20+14+14)×28

                      =1 344

Final answer :

surface area = 2 × base + lateral area

                     =  2 × 100 + 1344

                     =  200 + 1344

                     =  1544                

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<img src="https://tex.z-dn.net/?f=%5Csf%2020%3D9x-7" id="TexFormula1" title="\sf 20=9x-7" alt="\sf 20=9x-7" align="absmiddle" cl
Temka [501]

Answer:

x=3.

Add-on:

hope this helped at all.

8 0
2 years ago
Read 2 more answers
Hi please help me no links thank you
olya-2409 [2.1K]

Step-by-step explanation: (I'm not gonna' do it <em>all</em> for you tho)

to convert from <u>percent to fraction</u>:

70% = \frac{70}{100} =\frac{7}{10}

to convert from <u>fraction to percent</u>:

\frac{11}{20}=\frac{55}{100} = 55%

to convert from <u>fraction to decimal</u>:

\frac{3}{25} =\frac{12}{100} =0.12

to convert from <u>decimal to fraction</u>:

1.25=\frac{125}{100} =1\frac{25}{100} =1\frac{1}{4}

to convert from <u>percent to decimal</u>:

0.2% = \frac{0.2}{100} =0.002

to convert from <u>decimal to percent</u>:

0.4= (0.4*100)% = 40%

With that, you can solve the rest on your own

4 0
3 years ago
An archer has a mean distance of 1.6 inches and a MAD distance of 1.3 inches in the first round. In the second round, the archer
schepotkina [342]
I think it’s 1.5 cause it shows it
7 0
2 years ago
brooke found the equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form as follows​
Goryan [66]

Answer:

The equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form is \mathbf{y=-4x-3}

Step-by-step explanation:

Equation of line passing through the points (-7,25) and (-4,13) in slope-intercept form.

The general equation of slope-intercept form is: y=mx+b

First we need to find slope

The formula used for finding slope is: Slope=\frac{y_2-y_1}{x_2-x_1}

We are given: x_1=-7, y_1=25, x_2=-4, y_2=13

Putting values in formula and finding slope

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{13-25}{-4-(-7)}\\Slope=\frac{13-25}{-4+7}\\Slope=\frac{-12}{3}\\Slope=-4

So, slope m= -4

Now finding y-intercept

Using slope m=-4 and point (-7,25) we can find y-intercept

y=mx+b\\25=-4(-7)+b\\25=28+b\\b=25-28\\b=-3

So, y-intercept b =-3

Now, the equation of required line having slope m=-4 and  y-intercept b=-3 is:

y=mx+b\\y=-4x-3

So, the equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form is \mathbf{y=-4x-3}

3 0
2 years ago
What is the completely factored out form of d^4-8d^2+16
Lostsunrise [7]

d^4-8d^2+16

(d^2-4d)(d^2-4d)

(d-2)(d+2)(d-2)(d+2)

Option D is correct

8 0
3 years ago
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