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aleksklad [387]
3 years ago
11

On the set of axes below, Geoff drew rectangle ABCD. He will transform the rectangle by

Mathematics
1 answer:
Georgia [21]3 years ago
3 0

Answer:

C, exactly 28 square units

Step-by-step explanation:

This is because it's a translation, not a transformation. The size won't change, and therefore the area won't change. Just the position.

Since the area is 28 and it doesn't change, the answer is C.

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An economy package of cups has 840 green cups. If the green cups are 40% of the total package, how many cups are in the package?
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Answer:

336

Step-by-step explanation:

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A circle is represented by the equation below:
tangare [24]

Answer:

The circle is centered at (5, −7) and has a radius of 7.

Step-by-step explanation:

The standard form of the equation of a circle with center (a,b) and radius r is given as:

( {x - a)}^{2}  +  {(y - b)}^{2}  =  {r}^{2}

The given equation is

( {x - 5)}^{2}  +  {(y  + 7)}^{2}  =  49

We rewrite to look like the stay form:

( {x - 5)}^{2}  +  {(y   -  -  7)}^{2}  =   {7}^{2}

We now compare the two equations to get:

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Therefore the circle is centered at (5,-7) and has a radius of 7

8 0
3 years ago
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Help with the first question!! Is it right??
Aloiza [94]
No its 20 u should know that
6 0
3 years ago
Estimate the sum to the nearest hundreds 166+427
quester [9]
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5 0
4 years ago
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Jordan was given the expression 2x2^-3 x 2^-5 How should he write the expression as a fraction? Describe the exponent rules Jord
mariarad [96]

Answer:

2*2^{-3} * 2^{-5} =\frac{1}{128}

Step-by-step explanation:

Given

2*2^{-3} * 2^{-5}

Required

Write as a fraction

To do this, Jordan has to apply the following rules

<u>Negative Exponent rule:</u>

a^{-m} = \frac{1}{a^m}

<u>So, the expression is:</u>

2*2^{-3} * 2^{-5} = \frac{2}{2^3 * 2^5}

<u>To solve further, we apply the product rule of exponent</u>

a^m * a^n = a^{m+n}

<u>So, the expression is:</u>

2*2^{-3} * 2^{-5} =\frac{2}{2^{3+5}}

2*2^{-3} * 2^{-5} =\frac{2}{2^8}

<u></u>

<u>Evaluate the exponents</u>

2*2^{-3} * 2^{-5} =\frac{2}{256}

<u>Divide the numerator and denominator by 2</u>

2*2^{-3} * 2^{-5} =\frac{2/2}{256/2}

2*2^{-3} * 2^{-5} =\frac{1}{128}

4 0
4 years ago
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