Question

When 70. G of li3n(s) (molar mass 35 g/mol) reacts with excess h2(g), 8. 0 g of lih(s) is produced. The percent yield is closest to

Answer 1

Answer:

25%

Explanation:

Li3N(s) + 2 H2(g) ⇄ LiNH2(s) + 2 LiH(s)

70 g Li3N x 1 mol Li3N/35 g = 2 mol Li3N

2 mol Li3N x 2 mol LiH/1 mol Li3N

= 4 mol LiH x 7.05 g LiH/1 mol LiH = 28.20

percent yield = actual yield/theoretical yield x 100

8 g / 28.20 g ≈ 28%

28% is closest to 25% ap classrom