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2 years ago

Help pls. I don't know what to do :(

Mathematics

1 answer:

Dmitry_Shevchenko [17]2 years ago

8 0

Answer:

2.8

Explanation:

$r=\sqrt{\frac{v}{\pi h} } = \sqrt{\frac{213}{\pi (8.6)} } = 2.8078$

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Find the equation for the given graph. Slope: y-intercept: Equation:

Kay [80]

Answer:

slope:-1/2

y-int=5

Equation: y=-1/2x+5

Step-by-step explanation:

4 0

3 years ago

Pls Help!!! Just an example of how to do it pls!

telo118 [61]

10m + n^2/4

m = 5

n = 4

We can now substitute numbers in for the variables.

10(5) + (4)^2/4

50 + 4^2/4

50 + (4 * 4)/4

50 + 16/4

50 + 4

= 54

3 0

3 years ago

Read 2 more answers

Maria and Ming start at the same point and drive in opposite directions. Maria drives 54 mph and Ming drives 48 mph. How far apa

Wewaii [24]

Answer:

Step-by-step explanation:

Remark

They are going in opposite directions. That means you add the distances.

Total Distance = Maria_d + Ming_d

Ming

d = ?

r = 48 mph

t = 3 hour

d = r * t

d = 48 * 3

d = 144 miles

Maria

d = ?

r = 54 miles / hour

t = 3 hours

d = r * t

d = 54 * 3

d = 162

Total distance

Total = 162 + 144

Total = 306 miles

4 0

3 years ago

Car A gets 25 miles per gallon and costs $13,000. Car B is a hybrid that gets 45 miles per gallon, but costs $25,000. Assume you

Olenka [21]

The initial cost of car B is 25,000.

The cost of fuel consumed in n years by car B is
$=n\times \frac{15000\:miles}{year}\times \frac{1\:gallon}{45\:miles}\times \frac{4\:dollars}{gallon}$

Equate the initial cost to the cost of fuel
$25000=n\times \frac{15000\:miles}{year}\times \frac{1\:gallon}{45\:miles}\times \frac{4\:dollars}{gallon}$

$25000=\frac{4000n}{3}$

$n=\frac{25000\left(3\right)}{4000}$

$n=18.75$

It will take 18.75 years for Car B's better fuel economy to outweigh its higher initial cost.

5 0

4 years ago

Of 900 centimeters. The table shows the height of each bounce.

Mars2501 [29]

Answer:

Rounding to nearest tenth of centimeter, the ball bounces 192.1 cm high on the 5th bounce.

Explanation:

The ball is dropped from a height of 900 centimeters.

Since the heights form a geometric sequence, you can find a common ratio between consecutive terms. This is:

Height bounce 2 / height bounce 1 = 560 / 800 = 0.7

Height bound 3 / height bounce 2 = 392 / 560 = 0.7

Hence, the ratio of the geometric sequence is 0.7, and taking bounce 1 as the start of the sequence, the general term of the sequence is:

$a_n=800(0.7)^{n-1}$

With that formula you can find any term:

$n=1,a_1=800(0.7)^{(1-1)}=800(0.7)^0=800\\ \\ n=2,a_{2}=800(0.7)^{(2-1)}=800(0.7)=560\\ \\n=5,a_{5}=800(0.7)^{(5-1)}=800(0.4)^4=192.08$

Rounding to nearest tenth of centimeter, the ball bounces 192.1 cm high on the 5th bounce.

4 0

4 years ago