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3 years ago

Help plz due today

Mathematics

2 answers:

love history [14]3 years ago

8 0

Answer:

it should be (-8, -7)

Step-by-step explanation:

look up a coordinate plane

Romashka [77]3 years ago

5 0

Answer:

random

Step-by-step explanation:

You might be interested in

What are the solutions to 2x^2+7y=4 ? Select all that apply.

liberstina [14]

Answer:

x = -1/2 , 4

Step-by-step explanation:

1) If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.

2x+1=0

x−4=0

2) Set the first factor equal to 0.

2x+1=0

3) Subtract 1 from both sides of the equation.

2x=−1

4) Divide each term by 2 and simplify.

2x/2= −1/2

5) Cancel the common factor of 2.

x= −1/2

6) Move the negative in front of the fraction.

x = −1/2

7) Set the next factor equal to 0 and solve.

x=4

8) The final solution is all the values that make

(2x+1)(x−4) = 0 true.

9) x = −1/2 , 4

7 0

3 years ago

Assume that T is a linear transformation. Find the standard matrix of T. T: R^3 right arrow R^2 , T(e 1) =(1,2), and T(e2 ) =( -

irina [24]

Answer:

$A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]$

Step-by-step explanation:

Given

$T:R^3->R^2$

$T(e_1) = (1,2)$

$T(e_2) = (-4,6)$

$T(e_3) = (2,-6)$

Required

Find the standard matrix

The standard matrix (A) is given by

$Ax = T(x)$

Where

$T(x) = [T(e_1)\ T(e_2)\ T(e_3)]\left[\begin{array}{c}x_1&x_2&x_3\\-&&x_n\end{array}\right]$

$Ax = T(x)$ becomes

$Ax = [T(e_1)\ T(e_2)\ T(e_3)]\left[\begin{array}{c}x_1&x_2&x_3\\-&&x_n\end{array}\right]$

The x on both sides cancel out; and, we're left with:

$A = [T(e_1)\ T(e_2)\ T(e_3)]$

Recall that:

$T(e_1) = (1,2)$

$T(e_2) = (-4,6)$

$T(e_3) = (2,-6)$

In matrix:

$(a,b)$ is represented as: $\left[\begin{array}{c}a\\b\end{array}\right]$

So:

$T(e_1) = (1,2) = \left[\begin{array}{c}1\\2\end{array}\right]$

$T(e_2) = (-4,6)=\left[\begin{array}{c}-4\\6\end{array}\right]$

$T(e_3) = (2,-6)=\left[\begin{array}{c}2\\-6\end{array}\right]$

Substitute the above expressions in $A = [T(e_1)\ T(e_2)\ T(e_3)]$

$A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]$

Hence, the standard of the matrix A is:

$A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]$

6 0

3 years ago

26 = 3x - 2 - 7x show york work but please try to summarize you're explanation

Delvig [45]

26 = 3x - 2 - 7x
26 + 2 = -4x
28 / -4 = x
x = -7
Best answer me please!

6 0

3 years ago

Describe at least two differences between constructing an inscribed regular

Naddika [18.5K]

Answer:

They are very different because hexagons are amazing and squares are boring.

Step-by-step explanation:

4 0

3 years ago

9.4 The heights of a random sample of 50 college stu- dents showed a mean of 174.5 centimeters and a stan- dard deviation of 6.9

gladu [14]

Answer: a) (176.76,172.24), b) 0.976.

Step-by-step explanation:

Since we have given that

Mean height = 174.5 cm

Standard deviation = 6.9 cm

n = 50

we need to find the 98% confidence interval.

So, z = 2.326

(a) Construct a 98% confidence interval for the mean height of all college students.

$x\pm z\times \dfrac{\sigma}{\sqrt{n}}\\\\=(174.5\pm 2.326\times \dfrac{6.9}{\sqrt{50}})\\\\=(174.5+2.26,174.5-2.26)\\\\=(176.76,172.24)$

(b) What can we assert with 98% confidence about the possible size of our error if we estimate the mean height of all college students to be 174.5 centime- ters?

Error would be

$\dfrac{\sigma}{\sqrt{n}}\\\\=\dfrac{6.9}{\sqrt{50}}\\\\=0.976$

Hence, a) (176.76,172.24), b) 0.976.

8 0

3 years ago