The correct question is
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ABCD is a rectangle. what is the length of the diagonals if AC= 3y/5 and BD= 3(y-4)see the figure attached to better understand the problem
we know that
</span><span>Given AC and BD are diagonals. In a rectangle diagonals are equal.
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Therefore AC = BD
=> 3y/5 = 3y - 4
=> 3y = 5(3y - 4)
=> 3y = 15y - 20
=> 12y = 20
=> y = 20/12 = 5/3
Therefore AC = 3y/5
= 3(5/3)/5
= 1 units
and BD = 3y - 4
= 3(5/3) - 4
= 5 - 4
= 1 units
the answer is
The length of each diagonal is 1 units
Let A=(0,0)(x₁,x₂), B=(6,0)(x₂,y₂) and C=(0,6)(x₃,y₃)
Centroid of ΔABC is given by,
G(x,y) = [x₁+x₂+x₃/3 , y₁+y₂+y₃/3] = [0+6+0/3 , 0+0+6/3] = [2,2]
Answer:
3 km
Step-by-step explanation:
The area of a rectangle is given by the formula ...
A = LW
Filling in the given information, we can solve for the length.
1/4 = L·(1/12)
Multiplying by 12, we see that ...
3 = L
The array is 3 kilometers long.
Answer:
120 different ways
Step-by-step explanation:
you're going to use a permutation formula to figure out how many ways he can organize his blocks (5P5)
5!/0! = 5*4*3*2*1/1
this equals 120