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ipn [44]
3 years ago
13

HELP PLS WORTH 25 POINTS

Mathematics
1 answer:
Eva8 [605]3 years ago
7 0

Answer:

dd

Step-by-step explanation:

You might be interested in
2x + 3y= 39 <br><br> solve fir both x anddd y
Readme [11.4K]
X=15
Y=3

2(15)=30
3(3)=9
30+9=39
6 0
3 years ago
A) 10.5<br> b) 4<br> c) 10<br> d) 6
lara31 [8.8K]
The answer is b. You can find it by doing Pythagorean theorem. You know the radius and one side of the triangle, so now you solve for the other side by using that theorem. Once you have the length of the missing side you subtract it from the radius. (14.5 - 10.5).  

5 0
3 years ago
Subtract the sum of -1 37 and - 43 from the sum of - 103 and 27​
umka2103 [35]

Step-by-step explanation:

Hey, there!!

I hope you mean to subtract (-137) +(-43) from sum of -103 and 27.

First, add -103 + 27

= - 103 + 27

=  - 76

{As ( minus + plus )= subtracts with sign which has greator value. }

now,

( - 137) + ( - 43) =  - 180

{ minus + minus = add with minus sign}.

Now, subtracting -180 from -76.

=(-76) - (-180 )

Now, multiply the sign (- × -)= +

so, -180 becomes +180

= -76+180

= 104..... is answer.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

7 0
3 years ago
Read 2 more answers
In a class of 62 students, the number of females is one less than twice the number of males. How many females and how many males
lawyer [7]
Hopefully i helped you.
7 0
3 years ago
Suppose that a random sample of size 25 is to be selected from a population with mean 41 and standard deviation 9. What is the a
lorasvet [3.4K]

Answer:

The probability that X will be more than 0.5 away fro the population

mean is 0.7812 ⇒ answer a

Step-by-step explanation:

* Let us explain how to solve the problem

- The sample size n is 25

- The mean of the population μ is 41

- The standard deviation σ is 9

- We need to find the approximate probability that X will be more than

 0.5 away from the population mean

∵ z-score = (X - μ)/(σ/√n)

∵ X - μ = 0.5

- That means X > 41 + 0.5, OR X < 41 - 0.5

- Then we need to find P(X > 41.5) and P(X < 40.5)

∵ z = \frac{41.5-41}{\frac{9}{\sqrt{25}}} = 0.2778

∵ z = \frac{40.5-41}{\frac{9}{\sqrt{25}}} = -0.2778

- Let us use the normal distribution table to find the corresponding

  area to z-score

∵ P(z < 0.2778) = 0.6116

∵ P(z > -0.2778) = 0.3928

- P(40.5 < X < 41.5) = P( -0.2778 < z < 0.2778)

∴ The probability of X to be with in 0.5 = 0.6116 - 0.3928

∴ The probability of X to be with in 0.5 = 0.2188

∵ The probability of X to be more than 0.5 away from the population

   mean = 1 - 0.2188

∴ P(X > 41.5) OR P(X < 40.5) = 0.7812

* The probability that X will be more than 0.5 away fro the population

  mean is 0.7812

8 0
3 years ago
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