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mina [271]
3 years ago
9

I beg <3

Mathematics
1 answer:
IceJOKER [234]3 years ago
6 0

Answer:

Given:

A set of functions,

A. y = -(x-4)^2  

B. y=3(x- 4)^2

C. y = [x] + 4

D. y = -5x + 4.  

To Find:

The function whose range is (-infinity, 4].

Solution:

1. The function y = -(x-4)^2 has a minimum value of 0 and it is an increasing function. Hence the maximum value tends towards infinite. Hence the range is [0, infinite).

2. The function y = 3(x-4)^2 has a minimum value of 0 and it is an increasing function. Hence the maximum value tends towards infinite. Hence the range is [0, infinite).

3. y = [x] + 4 (where [x] = greatest integer function). This function is an increasing function with a minimum value towards negative infinity and the maximum value tends towards the positive side of infinity.  

=> Range of y = [x]  + 4 is (-infinite, infinite).

4. y = -5x+4 is a continuous increasing function without any exceptions.  

=> Range of y = -5x+4 is (-infinite,infinite)

Therefore, none of the functions has their range from (-infinity,4].

Step-by-step explanation:

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Answer:

10x . . . . . (Note the sign of the middle term is negative. 10x goes in the box.)

Step-by-step explanation:

The sum of the two roots is ...

... (5 -3i) +(5 +3i) = 10

In a quadratic with leading coefficient 1, the coefficient of the 1st-degree term is the opposite of the sum of the roots. Here, that means the middle term is -10x. The minus sign is given, so the answer is 10x.

_____

<em>How Do We Know?</em>

When "a" and "b" are roots of a quadratic in x, it has factors (x -a)(x -b). The product of those two factors is ...

... (x -a)(x -b) = x² -(a+b)x +ab

Here, that means the product of the factors (5 -3i)(5 +3i) is ab = 34, which it is. Their sum is (a+b) = 10, so the x-term is -(a+b)x = -10x.

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The value if y is -7

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What is the value of x?<br> 12 units<br> 15 units<br> 20 units<br> 25 units
Firlakuza [10]

Answer:

The answer is 12 units.

Step-by-step explanation:

Looking at the figure we see that

(1).9^2+x^2=SR^2

(2).16^2+x^2=RQ^2 and

(3).SR^2+RQ^2=(9+16)^2

Now from equations (1) and (2) we have values for SR^2 and RQ^2, so we put those into the equation (3) and get:

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3 years ago
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