Step-by-step explanation:
Length of the diagonal of the base (pythogorus theorem)
= sqrt(13^2 + 7.5^2)
= sqrt(169+56.25)
= sqrt(225.25)
= 15.01 in
But the drumsticks are 15.25 in long. So, they cannot lie flat on the diagonal along the base of the box.
Answer:
450m South
Step-by-step explanation:
Total distance traveled Northward :
1000m + 600m = 1600m Northward
Total distance traveled Southward :
1250m + 800m = 2050m
The Displacement :
Southward - Northward
2050m - 1650m
= 450m
Since, it covers more distance towards the south, then, direction is southward
450m South
Answer:
C. A graph titled Years Collecting Stamps versus Stamps in Collection has years collecting stamps on the x-axis and stamps in collection on the y-axis. Points are at (2, 100), (3, 100), (3, 125), (4, 150), (4, 175), (5, 175)
Step-by-step explanation:
In the x-axis goes the values from the column 'Number of years collecting stamps' of the table. And In the y-axis goes the values from the column 'Number of stamps in collection' of the table.
To make the graph identify each pair of values in the plane and mark it.
Answer: x = 7
Step-by-step explanation:
To solve the equation,
First step, open the bracket
3(x-5)-14=2(x-7)+2
3x -15 -14 = 2x -14 +2
Then, add the like terms
3x - 29 = 2x -16
Transpose the values at the right hand side to the left hand side
3x - 2x = -16 + 29
x = 7
The solution is:A mole of gas occupies 22.4 L A liter is 1000 cubic centimeters because 1 cubic centimeter = 1 mL
One Helium molecule (essentially one helium atom) has atomic mass 4 g/mol So for every 22400 cubic centimeters of volume, we have 4 grams of helium Density of helium = 4g / 22400 cm^3 = 1g / 5600 cm^3
Volume of a sphere = (4/3)(pi)r^3 Volume of the outside sphere (the entire sphere) is (4/3)(pi)(R+T)^3 Volume of the inside sphere (the hollow region) is (4/3)(pi)R^3
The difference for the volume of silver. (4/3)(pi)(R+T)^3 - (4/3)(pi)R^3 = (4/3)(pi)(3R^2T + 3RT^2 + T^3)
The density of silver is 10.5g/cm^3
So the mass of the silver is computed by:10.5*(4/3)(pi)(3R^2T + 3RT^2 + T^3) = (14*pi)(3R^2T + 3RT^2 + T^3) = (14pi)T(3R^2 + 3RT + T^2)
Now for the mass of helium: volume x density = (4/3)(pi)R^3 (1/5600) = (pi/4200)R^3
Set the two masses equal: (pi/4200)R^3 = (14pi)T(3R^2 + 3RT + T^2) R^3 = 58800*T(3R^2 + 3RT + T^2) R / T = 58800*(3R^2 + 3RT + T^2) / R^2 = 58800*( 3+T/R^2+(T/R)^2)
then solve for xx = T / R 1/x = 58800*( 3+x/R+x^2) 1/58800 = x (3 + x/R + x^2) 1/58800 = 3x + x^3 x^3 + 3x - 1/58800= 0 x = ~ 5.66893x10^(-6)
