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Julli [10]
2 years ago
13

Inequalities Which is the graph of the system x + 3y > -3 and y < 1/2x +1?

Mathematics
1 answer:
OLga [1]2 years ago
6 0

Answer:

the 4th graph.

Step-by-step explanation:

by solving for Y in the first equation, we get the y-intercept of -1 and the second equation has a y-intercept of 1. 4th graph is the only graph with those 2 intercepts

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Explain how to solve angle relationship problems
Nataly_w [17]

Answer:


Step-by-step explanation: Identify the angle relationships, set up the equation that will yield the unknown value, solve the equation for the unknown value, substitute the answer to determine the measurement of the angles then, check and verify your answer by measuring the angle with a protractor.


4 0
3 years ago
Which expression is equivalent to 10k+17-7j-18-11k?
balu736 [363]

Answer:

B. -7j-k-1

Step-by-step explanation:

Simplify:

1. IDENTIFY LIKE TERMS

<em>10k</em>+17-7j-18-<em>11k</em>

  • <em>10k and -11k are like terms since they have the same variable.</em>
  • 17 and -18 are like terms since they are regular numbers.
  • -7j has no like terms.

2. COMBINE LIKE TERMS

-7j-<em>k</em>-1

3 0
3 years ago
Read 2 more answers
What is the answer to |60| ____|-60|
Anna71 [15]

Answer:

=

Step-by-step explanation:

Equal too, you are finding the absolute value of both of them which means getting rid of any signs that is attached to them. 60 = 60

8 0
3 years ago
Read 2 more answers
What is the slope of the line that passes through these two points?
Dmitry_Shevchenko [17]

Answer:

undefined

Step-by-step explanation:

We can use the slope formula to find the slope

m = ( y2-y1)/(x2-x1)

   = ( 9-3) / ( 2-2)

   = 6/0

When we divide by zero, the result is undefined

This means the slope is undefined

7 0
2 years ago
Simplify the problem: Sin theta Sec Theta
kherson [118]

Answer:

\tan \theta

Step-by-step explanation:

We have to simplify the following expression as given by

\sin \theta \times \sec \theta

= \frac{\sin \theta}{\cos \theta}

= \tan \theta ( Answer )

Because, we know that \sec \theta =\frac{1}{\cos \theta} and \tan \theta = \frac{\sin \theta}{\cos \theta}

If we consider \sin \theta = \frac{Perpendicular}{Hypotenuse} and \sec \theta = \frac{Hypotenuse}{Base},

then \sin \theta \times \sec \theta = \frac{Perpendicular}{Hypotenuse}\times \frac{Hypotenuse}{Base} = \frac{Perpendicular}{Base}= \tan \theta

3 0
3 years ago
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