Pls answer what you can and I will give brainliest.

Which point on the graph is the solution to the system of linear equations? -2x=-y+4 x=-2

Elodia [21]

Answer:

The solution is (-2, 0)

Step-by-step explanation:

Re-write -2x=-y+4 x=-2 in column form:

x=-2

-2x=-y+4

Next, substitute -2 for x in the second equation:

-2(-2) = -y + 4, or:

4 = -y + 4. Thus, y must be 0.

The solution is (-2, 0)

4 0

3 years ago

A real estate agent has 8 master keys to open several new homes. Only 1 master key will open any given house. If 40% of these ho

riadik2000 [5.3K]

Answer:

Step-by-step explanation:

Suppose F represents the value that a room is unlocked.

Then, we can assume that the probability of unlocked homes is:

P(unlocked homes) = P(U)

P(unlocked homes) = 40%

P(unlocked homes) = 0.40

Also, let us represent the value of the locked room with G.

P(locked homes) = P(G)

P(locked homes) = (1 - 0.40)

P(locked homes) = 0.60

Let the probability of selecting a correct key be P(S)

It implies that for the agent to use 3 keys, we have a combination of $^8C_3$ possible ways for the set of keys.

Now; since only one will open the house, then:

P(select correct key) = P(S)

$P(S) = \dfrac{ (^1_1) (^7_2) }{ ^8_3 }$

$P(S) = \dfrac{21}{56}$

P(S) = 0.375

Finally, for the real estate agent to have access to specific homes supposing the agent select three master keys at random prior to the time he left his office, Then:

P(F ∪ (G∩S) = P(F) + P(G∩S)

P(F ∪ (G∩S) = P(F) + P(G) × P(S)

P(F ∪ (G∩S) = 0.40 + (0.60×0.375)

P(F ∪ (G∩S) = 0.40 + 0.225

P(F ∪ (G∩S) =0.625

5 0

3 years ago

This problem has been solved!See the answerA municipal bond service has three rating categories (A, B, and C). Suppose that in t

mariarad [96]

Answer:

a. $\frac{35}{51}$

b. $\frac{51}{100}$

c. $\frac{1}{5}$

Step-by-step explanation:

Suppose cities represented by C', suburbs represented by S and rural represented by R,

Let x be the total number of bonds issued throughout the US,

According to the question,

n(A) = 70% of x = 0.7x,

n(B) = 10% of x = 0.1x,

n(C) = 20% of x = 0.2x,

n(A∩C') = 50% of n(A) = 0.5 × 0.7x = 0.35x,

n(A∩S) = 20% of n(A) = 0.2 × 0.7x = 0.14x,

n(A∩R) = 30% of n(A) = 0.3 × 0.7x = 0.21x,

n(B∩C') = 40% of n(B) = 0.4 × 0.1x = 0.04x,

n(B∩S) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(B∩R) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(C∩C') = 60% of n(C) = 0.6 × 0.2x = 0.12x,

n(C∩S) = 15% of n(C) = 0.15 × 0.2x = 0.03x,

n(C∩R) = 25% of n(C) = 0.25 × 0.2x = 0.05x,

n(C') = n(A∩C') + n(B∩C') + n(C∩C') = 0.35x + 0.04x + 0.12x = 0.51x

n(S) = n(A∩S) + n(B∩S) + n(C∩S) = 0.14x + 0.03x + 0.03x = 0.20x

a. The probability that it will receive an A rating, if a new municipal bond is to be issued by a city,

$P(\frac{A}{C'})=\frac{P(A\cap C')}{P(C')}=\frac{0.35x/x}{0.51x/x}=\frac{0.35}{0.51}=\frac{35}{51}$

b. The proportion of municipal bonds are issued by cities = $\frac{n(C')}{x}$

$=\frac{0.51x}{x}$

$=\frac{51}{100}$

c. The proportion of municipal bonds are issued by suburbs = $\frac{n(S)}{x}$

$=\frac{0.20x}{x}$

$=\frac{20}{100}$

$=\frac{1}{5}$

3 0

3 years ago

7.89 greater or less than 7.189<br><br> 6.030 greater less or equal 6.03

NemiM [27]

7.89 is greater than 7.189, 6.03 is equal to 6.030, because that last zero doesn't really change anything it cancels itself out

5 0

3 years ago

Read 2 more answers

The Damon family owns a large grape vineyard in western New York along Lake Erie. The grapevines must be sprayed at the beginnin

solniwko [45]

Answer:

Step-by-step explanation:

This is a test of 2 population proportions. Let 1 and 2 be the subscript for the the vines infested using Pernod 5 and vines infested using Action. The population proportion of the vines infested using Pernod 5 and vines infested using Action would be p1 and p2 respectively.

p1 - p2 = difference in the proportion of the vines infested using Pernod 5 and vines infested using Action.

The null hypothesis is

H0 : p1 = p2

p1 - p2 = 0

The alternative hypothesis is

Ha : p1 ≠ p2

p1 - p2 ≠ 0

it is a two tailed test

Sample proportion = x/n

Where

x represents number of success(number of complaints)

n represents number of samples

For vines infested using Pernod 5,

x1 = 26

n1 = 410

p1 = 26/410 = 0.063

For vines infested using Action,

x2 = 39

n2 = 400

P2 = 39/400 = 0.098

The pooled proportion, pc is

pc = (x1 + x2)/(n1 + n2)

pc = (26 + 39)/(410 + 400) = 0.08

1 - pc = 1 - 0.08 = 0.92

z = (p1 - p2)/√pc(1 - pc)(1/n1 + 1/n2)

z = (0.063 - 0.098)/√(0.08)(0.92)(1/410 + 1/400) = - 0.035/0.019066

z = - 1.84

Since it is a two tailed test, the curve is symmetrical. We will look at the area in both tails. Since it is showing in one tail only, we would double the area

From the normal distribution table, the area below the test z score in the left tail 0.033

We would double this area to include the area in the right tail of z = 1.84 Thus

p = 0.033 × 2 = 0.066

By using the p value,

Since alpha, 0.01 < than the p value, 0.066, then we would fail to reject the null hypothesis.

Therefore, At a 1% level of significance, we cannot conclude that there is a difference in the proportion of vines infested using Pernod 5 as opposed to Action

5 0

3 years ago