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3 years ago

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What is the smallest integer greater than the square root of 68?

2 answers:

Talja [164]3 years ago

7 0

This question is essentially just determining whether you understand the definition of integers and square roots. The square root of a quantity is a number that when multiplied with itself gives that quantity. The square root of 68 is expressed as:

√68 = 8.25

The square root of 68 is roughly 8.25. Now, an integer is simply a whole number, which is a number that is not a fraction. Therefore, the smallest integer that is greater than 8.25 is simply the next whole number, which is 9.

The smallest integer greater than the square root of 68 is 9.

const2013 [10]3 years ago

5 0

What is the smallest integer greater than the square root of 68?

The answer is 9.

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The daily water consumption for an Ohio community is normally distributed with a mean consumption of 722,500 gallons and a stand

Allisa [31]

Answer:

0.0060

Step-by-step explanation:

The z-score is given by

<em>z = (866,475-722,500)/57,429 = 2.51 </em>

The probability is given by the area under the Normal curve N(0,1) to the <em>right</em> of 2.51

In <em>Excel </em> this value is found with the formula

=1-NORMDIST(2.51,0,1,1)

and in <em>OpenOffice Calc </em>

=1-NORMDIST(2.51;0;1;1)

<em> (NORMDIST(2.51;0;1;1) gives the area to the left of 2.51, so 1-NORMDIST(2.51;0;1;1) gives the area to the right of 2.51) </em>

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4 years ago

I need help<br> (percents)

Reptile [31]

CHOICE 1 $1250+5.5% of sales
$5000x0.055=$275+1250=$1525
$10,000x0.055=$550=1250=$1800

CHOICE 2 $2600=2% of sales
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$10000x0.02=$200+2600=$2800

So even though more is earned through percentage of sales in CHOICE 1, it doesn't make up for the larger monthly salary of CHOICE 2

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4 years ago

Help please! <br> find the area of the isoceles triangle

DiKsa [7]

Answer:

This is a long answer. I got 82.5

Step-by-step explanation:

Area of isoceles triangle is

$\frac{1}{2} (b)(h)$

where b is the base and h is height.

Let draw a altuide going through Point D that split side FE into 2 equal lines. Let call that point that is equidistant from FE, H.

Since it is a altitude,it forms a right angle. So angle H=90.

Angle H is equidistant from F and E so

FH=11

EH=11.

The height is still unknown.

We can use pythagorean theorem to find side h but we need to know the slanted side or side DF to use the theorem.

Using triangle DFH, we know that angle H is 90 and angle F is 34. So using triangle interior rule,Angle D equal 56.

We know side FH=11
We know Angle D equal 56
We are trying to find side DF
We know angle H equal 90

We can use law of sines to find side DF

$\frac{fh}{ \sin(d) } = \frac{df}{ \sin(h) }$

Plug in the numbers

$\frac{11}{ \sin(56) } = \frac{df}{ \sin(90) }$

sin of 90 =1 so

$\frac{11}{ \sin(56) } = df$

Side df is about 13.3 inches.

Since we know our slanted side is 13.3 we can set up our pythagorean theorem equation,

$(fh) {}^{2} + (dh) {}^{2} = df {}^{2}$

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$121 + dh {}^{2} = 176.89$

$(dh) {}^{2} = 55.89$

$\sqrt{55.89} = 7.5$

is approximately 7.5 so dh=7.5 approximately.

Now using base times height times 1/2 multiply them out

$\frac{1}{2} (22)(7.5)$

$82.5$

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