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Charra [1.4K]
3 years ago
14

What is the smallest integer greater than the square root of 68?

Mathematics
2 answers:
Talja [164]3 years ago
7 0
This question is essentially just determining whether you understand the definition of integers and square roots. The square root of a quantity is a number that when multiplied with itself gives that quantity. The square root of 68 is expressed as:

√68 = 8.25

The square root of 68 is roughly 8.25. Now, an integer is simply a whole number, which is a number that is not a fraction. Therefore, the smallest integer that is greater than 8.25 is simply the next whole number, which is 9.

The smallest integer greater than the square root of 68 is 9.
const2013 [10]3 years ago
5 0

What is the smallest integer greater than the square root of 68?

The answer is 9.


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Using the <u>normal distribution and the central limit theorem</u>, it is found that there is a 0.0166 = 1.66% probability of a sample proportion of 0.59 or less.

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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0.0166 = 1.66% probability of a sample proportion of 0.59 or less.

You can learn more about the <u>normal distribution and the central limit theorem</u> at brainly.com/question/24663213

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