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Vesnalui [34]
3 years ago
8

i need help! what is the volume of a 2.0 m solution of an acid needed to neutralize a 3.0 m solution of a 250 ml base?

Chemistry
1 answer:
diamong [38]3 years ago
8 0
Using the titration formula, we know that:

(2.0 M)(volume of acid)=(3.0 M)(250 mL)

volume of acid = (3.0)(250)/(2.0) = 375 mL
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where,

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T_{final}=87.29^oC

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