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3 years ago

Kaylee owns a small business selling clothing. She knows that in the last week 3

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

5 0

The debts card as a decimal to the nearest hundredth

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A can in the shape of a cylinder has a diameter of 6 centimeters and a height of 10 centimeters. Which measurement is closest to

VladimirAG [237]

Answer:

245.04

Step-by-step explanation:

A=2πrh+2πr2=2·π·3·10+2·π·32≈245.04423

u have to divide 6 and 2 to find the radius

hope this helps

7 0

3 years ago

Read 2 more answers

Find the surface area of each figure. Round your answers to the nearest hundredth, if necessary

jeyben [28]

Answer:

Step-by-step explanation:

7 0

3 years ago

∠ACE is formed by two secants intersecting outside of a circle. If minor arc BD = 28°, minor arc AB = 112°, and minor arc DE = 1

nignag [31]

D) 54 degrees:

BD+AB+DE+2ACE" on the circumference twice on the center"=360

28+112+112+2ACE=360

2ACE=108

∠ACE=54

8 0

3 years ago

Read 2 more answers

A rectangular prism with a volume of 6 cubic units is filled with cubes with side lengths of 1/2

Delicious77 [7]

Answer:

48 cubes are needed to fill the prism

Step-by-step explanation:

To solve this problem we first have to calculate the volume of the cube

1/2 units= 0.5 units

To calculate the volume of a cube we have to use the following formula:

v = volume

s = side = 0.5 u

v = s * s * s

we replace the values that we know

v = 0.5 u * 0.5 u * 0.5 u

v = 0.125 u³

The volume of the cube prism is 0.125 u³

Now we have to divide the volume of the prism by the volume of the cubes

6 u³ / 0.125 u³ = 48

48 cubes are needed to fill the prism

4 0

4 years ago

The angle 0 lies in Quadrant II . <br>Cos 0 = <br><img src="https://tex.z-dn.net/?f=%20-%20%20%5Cfrac%7B2%7D%7B3%7D%20" id="TexF

mel-nik [20]

Answer:

$\tan(\theta)=\frac{-\sqrt{5}}{2}$

Step-by-step explanation:

Since we are in quadrant 2, sine is positive. Since sine is positive and cosine is negative, then tangent is negative.

Now I'm going to find the sine value of this angle given using one of the Pythagorean Identities, namely $\sin^2(\theta)+\cos^2(\theta)=1$ .

If given $\cos(\theta)=\frac{-2}{3}$ , then we have $\sin^2(\theta)+(\frac{-2}{3})^2=1$ by substitution of $\cos(\theta)=\frac{-2}{3}$ .

Let's solve:

$\sin^2(\theta)+(\frac{-2}{3})^2=1$ for $\sin(\theta)$ .

$\sin^2(\theta)+\frac{4}{9}=1$

Subtract 4/9 on both sides:

$\sin^2(\theta)=1-\frac{4}{9}$

Simplify:

$\sin^2(\theta)=\frac{5}{9}$

Square root both sides:

$\sin(\theta)=\sqrt{\frac{5}{9}}$

$\sin(\theta)=\frac{\sqrt{5}}{\sqrt{9}}$

$\sin(\theta)=\frac{\sqrt{5}}{3}$

===========

$\tan(\theta)=\frac{\sin(\theta)}{\cos(\theta)}=\frac{\frac{\sqrt{5}}{3}}{\frac{-2}{3}}$

Multiplying top and bottom by 3 gives:

$\tan(\theta)=\frac{\sqrt{5}}{-2}$

I'm going to move the factor of -1 to the top:

$\tan(\theta)=\frac{-\sqrt{5}}{2}$

7 0

3 years ago