∠ACE is formed by two secants intersecting outside of a circle. If minor arc BD = 28°, minor arc AB = 112°, and minor arc DE = 1 12°, what is the measure of ∠ACE? A) 14° B) 28° C) 40° D) 54°
2 answers:
D) 54 degrees: BD+AB+DE+2ACE" on the circumference twice on the center"=360 28+112+112+2ACE=360 2ACE=108 ∠ACE=54
Answer:
its 40 degrees
Step-by-step explanation:
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