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WITCHER [35]
2 years ago
10

Nina’s garden is 4 1/5 meters long and 3/10 meter wide. What is the area of Nina’s garden

Mathematics
1 answer:
docker41 [41]2 years ago
8 0

Answer:

12.6

Step-by-step explanation:

1/5 = .2

3/10 = .3

4.2 x .3 = 12.6

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I marked all 3 parts. I need to know part C (the shaded part). anybody mind helping?​
Mnenie [13.5K]

Answer:

Area of shaded part ABCEF = 66 sq.cm

Step-by-step explanation:

AB = 8cm

CD = 8cm

Let DE = x cm

CE = 3x cm

CD =  CE + DE = 8cm

        x + 3x = 8

4x = 8

x = 8/4 = 2 cm

DE = 2cm

CE = 3 * 2 = 6 cm

Area of triangle ADE = 1/2 * base * height

                                   = 1/2 * DE * AD

                                    = 1/2 * 2 * 11 = 11 sq. cm

Area of triangle AEF = Area of triangle ADE = 11 sq. cm

Area of Rectangle ABCD =  l * b = 8 * 11 = 88 sq.cm

Area of shaded part ABCEF =  Area of Rectangle ABCD - (Area of triangle AEF + Area of triangle ADE)

    = 88 - ( 11 + 11 )  = 88 -22 = 66 sq.cm

6 0
3 years ago
"The product of four and a<br> number is more than ten."<br> ( write as an inequality thx)
lubasha [3.4K]

Answer:

4x > 10

Step-by-step explanation:

4x > 10

6 0
3 years ago
What is 0.416666667 as a fraction
pogonyaev
It's 416,666,667/1,000,000,000. //// If you said that the 6s keep going and never end, then it would be the decimal form of 5/12 .
8 0
3 years ago
How do I do this problem? Evaluate each expression <br> (-4)-(-6)-(2-1)
natita [175]

Answer:

1

Step-by-step explanation:

(-4) - (-6) - (2-1)

-4 + 6 -2 +1

1

6 0
3 years ago
The length of a box is 4 inches longer than its width, and the height is 2 inches shorter than the width. which equation can you
andreev551 [17]
L=w+4 this shows the length is 4 inches longer than width
h=w-2 this shows the height is 2 inches shorter than the width
volume=lwh
so 240=lwh=(w+4)(w)(w-2)
simplify and solve to find the width then you can use that to find the other values as well.
3 0
3 years ago
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