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Rom4ik [11]
3 years ago
7

20%5C%3A%20a%20%2B%20b%20%3D%202" id="TexFormula1" title="if \: \frac{ \sqrt{2} }{2} a + b = 0 \: and \: a + b = 2" alt="if \: \frac{ \sqrt{2} }{2} a + b = 0 \: and \: a + b = 2" align="absmiddle" class="latex-formula">
then a×b=?
Mathematics
1 answer:
Ainat [17]3 years ago
8 0
2 x 1=2 or you can have 1+1=2
You might be interested in
X=2t/t^2 +1 and y=2t/t^2 +1 <br>Find dy/dx​
zhenek [66]

Answer:

dy/dx=1

Hope this helps! Please vote brainliest! :)

7 0
2 years ago
The sum of 4 times a number and -2 is equal to the sum of 5 times the number and -2. Find the number
MArishka [77]
4n(-2)=(5)(-2)
-8n=-10
—— —-
-8 -8

n= 5/4
n= 1 1/4

So the final answer is n= 1.25
6 0
3 years ago
What is the principal value cost of cos​−1<br> ​(0.69)
CaHeK987 [17]
We are asked to find the principal value of
cos ⁻¹ (0.69)
which is just the least positive angle
cos ⁻¹ (0.69) = 46.37°
Other values of 
cos ⁻¹ (0.69) is
46.37° - 180° n
where n is a whole number
6 0
3 years ago
Please help me thank youuu(๑&gt;◡&lt;๑)
coldgirl [10]

Answer:

  • 15x -45
  • 3(5x -15)

Step-by-step explanation:

The expression can be fully factored as ...

  3·5·(x-3)

Equivalent expressions can be formed by eliminating parentheses to give ...

  15x -45

or by combining different pairs of factors:

  • 3(5x -15)
  • 5(3x -9)

Of course any of the terms can be broken apart and/or combined in different ways:

  = 15(x -2) -15

  = (7x -7) + 2(4x -19)

6 0
3 years ago
Find the number b such that the line y = b divides the region bounded by the curves y = 25x2 and y = 1 into two regions with equ
Dennis_Churaev [7]

Answer:

y=1/∛4 divides the area in half

Step-by-step explanation:

since the minimum value of x² is 0 (for x=0 ) and for y=1

1 = 25*x² → x= ±√(1/25) = ±1/5

then the total area between y=1  and y = 25*x²  is bounded to  x=±1/5 and y=0 . Since there is a direct relationship between x and y , we can find the value of x=a that divides the region in 2 of the same area. thus

Area below x=C = Area above x=C

Area below x=C = Total area -  Area below x=C

2*Area below x=C = Total area

Area below x=C = Total area /2

∫ 25*x² dx from x=c to x=-c =  1/2 ∫ 25*x² dx from x=1/5  to x=-1/5

25*[c³/3 - (-c)³/3] = 25/2 * [(1/5)³/3 - (-1/5)³/3]

2*c³/3 = (1/5)³/3

c = 1/(5*∛2)

thus

y=25* x²  = 25*[1/(5*∛2)]² = 1/∛4

thus the line y=1/∛4 divides the area in half

4 0
2 years ago
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