Answer:
n = 15/ 5m - 14
Step-by-step explanation:
Given that
Sin θ = a/b
LHS = Sec θ + Tan θ
⇛(1/Cos θ) + (Sin θ/ Cos θ)
⇛(1+Sin θ)/Cos θ
We know that
Sin² A + Cos² A = 1
⇛Cos² A = 1-Sin² A
⇛Cos A =√(1-Sin² A)
LHS = (1+Sin θ)/√(1- Sin² θ)
⇛ LHS = {1+(a/b)}/√{1-(a/b)²}
= {(b+a)/b}/√(1-(a²/b²))
= {(b+a)/b}/√{(b²-a²)/b²}
= {(b+a)/b}/√{(b²-a²)/b}
= (b+a)/√(b²-a²)
= √{(b+a)(b+a)/(b²-a²)}
⇛ LHS = √{(b+a)(b+a)/(b+a)(b-a)}
Now, (x+y)(x-y) = x²-y²
Where ,
On cancelling (b+a) then
⇛LHS = √{(b+a)/(b-a)}
⇛RHS
⇛ LHS = RHS
Sec θ + Tan θ = √{(b+a)/(b-a)}
Hence, Proved.
<u>Answer</u><u>:</u> If Sinθ=a/b then Secθ+Tanθ=√{(b+a)/(b-a)}.
<u>also</u><u> read</u><u> similar</u><u> questions</u><u>:</u><u>-</u> i) sin^2 A sec^2 B + tan^2 B cos^2 A = sin^2A + tan²B..
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Sec x -tan x sin x =1/secx Help me prove it..
brainly.com/question/20791199?referrer
Answer:
x = ±√17
Step-by-step explanation:
Isolate the variable, x. Note the equal sign, what you do to one side of the equation, you do to the other.
Also note that the x has a power of 2. To isolate the x, simply root both sides of the equation.
x² = 17 ; √x² = √17 ; x = ±√17
~
12 & 5. both these numbers only have 60 in common(12*5=60) and 5 is 7 less than 12(7+5=12)
r²h
= 5.8% increase
