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svetlana [45]
3 years ago
8

Brandon has 10 but each bag has 6 chocolates how many chocolates does he have in total

Mathematics
2 answers:
sp2606 [1]3 years ago
7 0
Brandon has 10 but each bag has 6 chocolates how many chocolates does he have in total
ycow [4]3 years ago
4 0

Answer:

10 what

Step-by-step explanation:

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Is (a + b) and (a - b)? perfect square trinomials?<br> O True<br> O False
lisabon 2012 [21]

Answer:

False

Step-by-step explanation:

Pos and negs cannot be perfect square trinomials

8 0
3 years ago
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A farmer sells 8.9 kilograms of pears and apples at the farmer's market. 1 4 of this weight is pears, and the rest is apples. Ho
dmitriy555 [2]

Answer:

7.5 kilograms of apples

Step-by-step explanation:

Take the total amount and subtract the amount of pears.

8.9-1.4=7.5

4 0
3 years ago
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Given: △ABC, m∠A=60° m∠C=45°, AB=8 Find: Perimeter of △ABC, Area of △ABC
jarptica [38.1K]

We are given

△ABC, m∠A=60° m∠C=45°, AB=8

Firstly, we will find all angles and sides

Calculation of angle B:

we know that sum of all angles is 180

m∠A+ m∠B+m∠C=180

we can plug values

60°+ m∠B+45°=180

m∠B=75°

Calculation of BC:

we can use law of sines

\frac{AB}{sin(C)}=\frac{BC}{sin(A)}

now, we can plug values

\frac{8}{sin(45)}=\frac{BC}{sin(60)}

BC=\frac{8}{sin(45)} \times sin(60)

BC=9.798

Calculation of AC:

\frac{AB}{sin(C)}=\frac{AC}{sin(B)}

now, we can plug values

\frac{8}{sin(45)}=\frac{AC}{sin(75)}

AC=\frac{8}{sin(45)} \times sin(75)

AC=10.928

Perimeter:

p=AB+BC+AC

we can plug values

p=10.928+8+9.798

p=28.726

Area:

we can use formula

A=\frac{1}{2}AB \times AC \times sin(A)

now, we can plug values

A=\frac{1}{2}8 \times 10.928 \times sin(60)

A=37.85570...............Answer

6 0
4 years ago
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Find the 14th term of the arithmetic sequence - 4x - 1, - 9x - 6 , -14x-11
Yanka [14]

Answer:

-69x-66

Step-by-step explanation:

1) given: a₁=-4x-1; a₂=-9x-6; a₃=-14x-11. Find: a₁₄-?

2) a₁₄=a₁+13d, where d - the difference between neighbor-terms;

3) d=a₂-a₁; ⇔ d= -9x-6+4x+1= -5x-5;

4) a₁₄= -4x-1+13*(-5x-5)= -69x-66.

3 0
3 years ago
First five terms of n2+5
artcher [175]
a_n=n^2+5\\\\a_1=1^2+5=1+5=6\\\\a_2=2^2+5=4+5=9\\\\a_3=3^2+5=9+5=14\\\\a_4=4^2+5=16+5=21\\\\a_5=5^2+5=25+5=30
8 0
3 years ago
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