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Olenka [21]
2 years ago
13

Can some help meeeeeeeee?

Mathematics
1 answer:
Natali [406]2 years ago
8 0

Answer:

$46.54

Step-by-step explanation:

A=P(1+r/n)^nt

P=220

r=.0325

n=1

t=6

A=266.54

A=P+I

266.54=220+I

I=46.54

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Suppose wellington pours 1/8 gallons from the remaining juice into a glass. He pours the same amount into more glasses until the
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Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 3x(1/3) + 6x(4/3). You must justi
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Answer:

We have an extrema (local minimum) at x = -0.125

An inflection point at x = 0.25

Step-by-step explanation:

The given function is given as follows;

f(x) = 3x^{1/3} + 6x^{4/3}

At the extrema points, f'(x) = 0 which gives;

0 = \dfrac{\mathrm{d}  \left (3x^{1/3} + 6x^{4/3}  \right )}{\mathrm{d} x} = \dfrac{(8 \cdot x+1) \times \sqrt[0.3]{x}  }{x}

(8x + 1) =x- (0/((x)^(1/0.3)) = 0

x = -1/8 = -0.125

f''(x)  gives;

f''(x) = \dfrac{\mathrm{d}  \left (\dfrac{(8 \cdot x+1) \times \sqrt[0.3]{x}  }{x} \right )}{\mathrm{d} x} = \dfrac{ \left (\dfrac{8}{3}\cdot x^2 - \dfrac{2}{3} \cdot x \right ) \times \sqrt[0.3]{x} }{x^3}

Substituting x = -0.125 gives f''(x) = 32 which is a minimum point

The inflection point is given as follows;

\dfrac{ \left (\dfrac{8}{3}\cdot x^2 - \dfrac{2}{3} \cdot x \right ) \times \sqrt[0.3]{x} }{x^3} = 0

\dfrac{8}{3}\cdot x^2 - \dfrac{2}{3} \cdot x \right  }{} = 0 \times \dfrac{x^3}{ \sqrt[0.3]{x}}

\dfrac{8}{3}\cdot x - \dfrac{2}{3}  \right  }{} = 0

x = 2/3×3/8 = 1/4 = 0.25

We check the value of f''(x) at x = 0.24 and 0.26 to determine if x = 0.25 is an inflection point as follows;

At x = 0.24,   f''(x) = -0.288

At x = 0.26,   f''(x) = 0.252

0.25 is an inflection point

4 0
4 years ago
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