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slavikrds [6]
3 years ago
10

Mariana gets $15 per hour working at McDonald's and Jayvon gets $15 per hour as well. Jayvon had $50 in the

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
3 0

Answer:

What r the options?

Step-by-step explanation:

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Nana76 [90]

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no I do not agree, Because it doesn't make since

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2 years ago
Please help!!!! I'll make you Brainliest!! Thanks!!
alexandr1967 [171]
Im thinking it whould be c
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3 years ago
Is 5.5 greater then 5.7
ivann1987 [24]
No, it is .2 less than 5.7
3 0
3 years ago
Read 2 more answers
Answer 322.788 hope this helped
erma4kov [3.2K]

Answer:

322.788?

Step-by-step explanation:

7 0
3 years ago
The weights of college football players are normally distributed with a mean of 200 pounds and a standard deviation of 50 pounds
Feliz [49]

Answer:

0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 200, \sigma = 50

Find the probability that he weighs between 170 and 220 pounds.

This is the pvalue of Z when X = 220 subtracted by the pvalue of Z when X = 170.

X = 220

Z = \frac{X - \mu}{\sigma}

Z = \frac{220 - 200}{50}

Z = 0.4

Z = 0.4 has a pvalue of 0.6554

X = 170

Z = \frac{X - \mu}{\sigma}

Z = \frac{170 - 200}{50}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.6554 - 0.2743 = 0.3811

0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.

6 0
4 years ago
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