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2 years ago

13

Given that cos 63°≈ 0.454, enter the sine of a complementary angle. sin

1 answer:

jek_recluse [69]2 years ago

4 0

Answer:

$\cos(63^\circ)$ is the same as $\sin(27^\circ)$ by co-function identities

Step-by-step explanation:

Remember that complementary angles add up to 90°. The angle that i s complementary to 63° is 27°.

Also recall the co-function identities:

sin (90° – x) = cos x
cos (90° – x) = sin x

This means that $\cos(90^\circ-27^\circ)=\sin(27^\circ)\approx0.454$ .

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Ray's pizza serves small and LG pizza. a small pizza has a diameter of 10inches and is sliced into 6 equal slices.a large pizza

Andrew [12]

Amount of pizza eaten by Charlie.

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Amount of pizza eaten by Julie

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3 years ago

Find the area of the figure below. Round your answer to one decimal place.

MAVERICK [17]

Answer: 57.1 (rounded)

Step-by-step explanation:

Area of triangle formula: 1/2 x base x height

Area of a semicircle: 1/2 x pi x r^2

(1/2 x 8 x 8) + (1/2 x pi x 4^2)

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2 years ago

In circle P, EG and FH are diameters.<br> What is m EH?

zvonat [6]

Answer:

$m(\widehat{EH})$ = 130°

Step-by-step explanation:

Angles subtended at the center by the arcs $(\widehat{HG})$ and $(\widehat{EF})$ are ∠HPG and ∠EPF.

Since these angles are the vertical angles both will be equal.

m∠HPG ≅ m∠EPF

3x - 10 = 2x + 10

3x - 2x = 10 + 10

x = 20

Therefore, $m(\widehat{HG})=(3\times 20) - 10$

= 50°

Similarly $m(\widehat{EF})$ = 50°

In the same way angles subtended at the center will be equal.

m∠EPH ≅ m∠FPG

and $m(\widehat{EH})=m(\widehat{FG})$

Since $m(\widehat{EH})+m(\widehat{FG})+m(\widehat{EF})+m(\widehat{HG})=360$ °

$m(\widehat{EH})+m(\widehat{EH})+50+50=360$

$2m(\widehat{EH})=360-100$

$m(\widehat{EH})=130$

Therefore, measure of arc EH = 130°

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3 years ago

Find the absolute maximum and minimum values of the following function on the given interval. If there are multiple points in a

Bond [772]

$f(x)=3\sin x+3\cos x\implies f'(x)=3\cos x-3\sin x$

$f$ has critical points where $f'=0$ :

$3\cos x-3\sin x=0\implies\cos x=\sin x\implies\tan x=1\implies x=\pm\dfrac\pi4+2n\pi$

where $n$ is any integer. We get solutions in the interval $\left[0,\frac\pi3\right]$ for $n=0$ , for which $x=\frac\pi4$ .

At this critical point, we have $f\left(\frac\pi4\right)=3\sqrt2\approx4.243$ .

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So we have the extreme values

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3 years ago

The graph of a quadratic function has roots at -3 and -7 and a vertex at (-5, 4). What is the equation of the function in vertex

melomori [17]

Answer:

y = -(x + 5)² + 4

Step-by-step explanation:

The roots are -3 and -7, so:

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y = -(x + 5)² + 4

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3 years ago