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2 years ago

I really need help, I'm struggling. Question is in image.

Mathematics

1 answer:

damaskus [11]2 years ago

5 0

Answer:

See below ~

Step-by-step explanation:

(a)

Original Temp : -7°F
Temp change : 15°F
⇒ -7°F + 15°F = 8°F

(b)

Temp in Juneau = -28°F
Temp in Montreal = -15°F
Difference in temp = -28 - (-15)
-28 + 15 = -13°F lower

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Find the area of each figure

prohojiy [21]

Answer:

A=120

B=20

C=20

Total area=160 cm2

This is really weird because the numbers dont look proportional to the shape but according to the data it should be correct :/

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2 years ago

Read 2 more answers

Last question for the night.

horsena [70]

Answer:

third option

Step-by-step explanation:

$\frac{16 {x}^{2} }{4x + 24} \div \frac{8 {x}^{2} - 40x}{ {x}^{2} - 36} \\ = \frac{16 {x}^{2} }{4(x + 6)} \times \frac{(x + 6)(x - 6)}{8x(x - 5)} \\ = \frac{16 {x}^{2} }{4} \times \frac{x - 6}{8x(x - 5)} \\ = \frac{x}{1} \times \frac{x - 6}{2(x - 5)} \\ = \frac{x(x + 6)}{2x - 10}$

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4 0

3 years ago

Pls help me i need this asap

Bingel [31]

Answer:

Chandelier 6ll you multiple 6 x2 you will get 12

3 0

3 years ago

A quantitative data set has mean 23 and standard deviation 2. At least what percentage of the observations lie between 15 and 31

Elan Coil [88]

Answer:

Atleast 93.75% of data lies between 15 and 31.

Step-by-step explanation:

We are given the following in the question:

Mean = 23

Standard deviation = 2

We have to find he data lying between 15 and 31.

$15 = 23 - 4(2) = \mu - 4\sigma\\31 = 23 + 4(2) = \mu + 4\sigma$

Thus, we have to find the data lying within 4 standard deviation from the mean.

Chebyshev's Theorem:

According to this theorem atleast $1 - \dfrac{1}{k^2}$ percent of data lies within k standard deviation of mean.
For k = 4.

$1 - \dfrac{1}{(4)^2} = 0.9375 = 93.75\%$

Thus, atleast 93.75% of data lies between 15 and 31.

7 0

3 years ago

Can someone please help

USPshnik [31]

Answer:

-40

Step-by-step explanation:

Since x is 10 you need to multiply 10*-4 which equals -40.

8 0

3 years ago

I really need help, I'm struggling. Question is in image. ​

I really need help, I'm struggling. Question is in image.