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schepotkina [342]
2 years ago
15

-5=0.1x-8.5 what is the answer

Mathematics
2 answers:
ipn [44]2 years ago
7 0

Answer:  x = 35

Step-by-step explanation:

-5 = 0.1x - 8.5

Step 1: Rewrite the equation:

0.1x - 8.5 = -5

Step 2: Add 8.5 on both sides.

          0.1x = 3.5

Step 3: Divide 0.1 on both sides.

               x = 35

astra-53 [7]2 years ago
4 0

Answer:

x = 35

Step-by-step explanation:

hope this helps

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Pleasantburg has a population growth model of P(t)=at2+bt+P0 where P0 is the initial population. Suppose that the future populat
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Answer:

The population will reach 34,200 in February of 2146.

Step-by-step explanation:

Population in t years after 2012 is given by:

P(t) = 0.8t^{2} + 6t + 19000

In what month and year will the population reach 34,200?

We have to find t for which P(t) = 34200. So

P(t) = 0.8t^{2} + 6t + 19000

0.8t^{2} + 6t + 19000 = 34200

0.8t^{2} + 6t - 15200 = 0

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

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In this question:

0.8t^{2} + 6t - 15200 = 0

So a = 0.8, b = 6, c = -15200

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\bigtriangleup = 6^{2} - 4*0.8*(-15100) = 48356

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t_{2} = \frac{-6 - \sqrt{48356}}{2*0.8} = -141.64

We only take the positive value.

134 years after 2012.

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So the population will reach 34,200 in February of 2146.

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3 years ago
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Answer:

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