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3 years ago

PLEASE HELP !! ILL GIVE BRAINLIEST EXTRA 40 POINTS DONT SKIP :(( .!

Mathematics

1 answer:

UNO [17]3 years ago

6 0

Answer:

D ez

Step-by-step explanation:

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Fill in the table and graph plz

ololo11 [35]

You have to plug in the numbers for x and then solve.

For example, when it says y=2x-4, you put -2 and the numbers below it for x and then solve.

(I don't want to give you the answer to everything and want to help you understand how to do it.)

8 0

3 years ago

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Viefleur [7K]

Answer:

x >4

Step-by-step explanation:

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8 0

3 years ago

Solve the following three equations.

tester [92]

Answer:

#1 : -2=n

#2: x=-3

#3: v=8

Step-by-step explanation:

the pictures are the explination

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5 0

4 years ago

A random sample of five Galaxy 8 smartphones is selected from the production line after final assembly, and the result of the we

zepelin [54]

<h2>Answer with explanation:</h2>

Given : A random sample of five Galaxy 8 smartphones is selected from the production line after final assembly, and the result of the weight control measurement is (in grams) are :

X= 155.1, 154.8, 155.5, 155.3, and 154.6.

here, n=5

The average weight : $\overline{x}=\dfrac{\sum^{i=5}_{i=1}x_i}{n}$

$=\dfrac{155.1+154.8+155.5+155.3+154.6}{5}\\\\=\dfrac{775.3}{5}=155.06$

∴ Average weight ( $\overline{x}$ )=155.06 grams

Uncertainty = Standard deviation: $\sigma=\sqrt{\dfrac{\sum^{i=5}_{i=1}(x_i-\overline{x})^2}{n}}$

$=\sqrt{\dfrac{(0.04)^2+(-0.26)^2+(0.44)^2+(0.24)^2+(-0.46)^2}{5}}$

$=\sqrt{\dfrac{0.532}{5}}=\sqrt{0.1064}=0.326190128606\approx0.33$

i.e. Its uncertainty : $\sigma=0.33$

The fractional uncertainty = $\dfrac{\sigma}{\overline{x}}$

$=\dfrac{0.33}{155.06}=0.00212820843544\approx0.002$

7 0

4 years ago

Verify that:

Lelu [443]

Answer:

See Below.

Step-by-step explanation:

Problem 1)

We want to verify that:

$\displaystyle \left(\cos(x)\right)\left(\cot(x)\right)=\csc(x)-\sin(x)$

Note that cot(x) = cos(x) / sin(x). Hence:

$\displaystyle \left(\cos(x)\right)\left(\frac{\cos(x)}{\sin(x)}\right)=\csc(x)-\sin(x)$

Multiply:

$\displaystyle \frac{\cos^2(x)}{\sin(x)}=\csc(x)-\sin(x)$

Recall that Pythagorean Identity: sin²(x) + cos²(x) = 1 or cos²(x) = 1 - sin²(x). Substitute:

$\displaystyle \frac{1-\sin^2(x)}{\sin(x)}=\csc(x)-\sin(x)$

Split:

$\displaystyle \frac{1}{\sin(x)}-\frac{\sin^2(x)}{\sin(x)}=\csc(x)-\sin(x)$

Simplify:

$\csc(x)-\sin(x)=\csc(x)-\sin(x)$

Problem 2)

We want to verify that:

$\displaystyle (\csc(x)-\cot(x))^2=\frac{1-\cos(x)}{1+\cos(x)}$

Square:

$\displaystyle \csc^2(x)-2\csc(x)\cot(x)+\cot^2(x)=\frac{1-\cos(x)}{1+\cos(x)}$

Convert csc(x) to 1 / sin(x) and cot(x) to cos(x) / sin(x). Thus:

$\displaystyle \frac{1}{\sin^2(x)}-\frac{2\cos(x)}{\sin^2(x)}+\frac{\cos^2(x)}{\sin^2(x)}=\frac{1-\cos(x)}{1+\cos(x)}$

Factor out the sin²(x) from the denominator:

$\displaystyle \frac{1}{\sin^2(x)}\left(1-2\cos(x)+\cos^2(x)\right)=\frac{1-\cos(x)}{1+\cos(x)}$

Factor (perfect square trinomial):

$\displaystyle \frac{1}{\sin^2(x)}\left((\cos(x)-1)^2\right)=\frac{1-\cos(x)}{1+\cos(x)}$

Using the Pythagorean Identity, we know that sin²(x) = 1 - cos²(x). Hence:

$\displaystyle \frac{(\cos(x)-1)^2}{1-\cos^2(x)}=\frac{1-\cos(x)}{1+\cos(x)}$

Factor (difference of two squares):

$\displaystyle \frac{(\cos(x)-1)^2}{(1-\cos(x))(1+\cos(x))}=\frac{1-\cos(x)}{1+\cos(x)}$

Factor out a negative from the first factor in the denominator:

$\displaystyle \frac{(\cos(x)-1)^2}{-(\cos(x)-1)(1+\cos(x))}=\frac{1-\cos(x)}{1+\cos(x)}$

Cancel:

$\displaystyle \frac{\cos(x)-1}{-(1+\cos(x))}=\frac{1-\cos(x)}{1+\cos(x)}$

Distribute the negative into the numerator. Therefore:

$\displaystyle \frac{1-\cos(x)}{1+\cos(x)}=\displaystyle \frac{1-\cos(x)}{1+\cos(x)}$

3 0

3 years ago

PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA 40 POINTS* DONT SKIP :(( .!

PLEASE HELP !! ILL GIVE BRAINLIEST EXTRA 40 POINTS DONT SKIP :(( .!