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Dimas [21]
2 years ago
9

PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA 40 POINTS* DONT SKIP :(( .!

Mathematics
1 answer:
UNO [17]2 years ago
6 0

Answer:

D ez

Step-by-step explanation:

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Polygon LMNOP was transformed to create polygon L'M'N'O'P'. Which angle corresponds to N?
Svetach [21]

Answer:

N'

Step-by-step explanation:

L corresponds to L'

M corresponds to M'

N corresponds to N'

O corresponds to O'

P corresponds to P'

After the transformation if you copy and paste your picture over the new picture, the corresponding angles should lay on top of each other.

8 0
3 years ago
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What is the area of a regular nonagon with 10 cm sides and an apothem if 6cm?
bearhunter [10]

Answer:

The area of the nonagon is 270cm²

Step-by-step explanation:

The area of a regular polygon is given by

=  \frac{1}{2} ap

where 'a' is the apothem and 'p' is the perimeter.

The apothem is a=6cm.

The perimeter is p=9×10=90cm.

We substitute the apothem and the perimeter to get:

=  \frac{1}{2}  \times 6 \times 90 {cm}^{2}

= 270 {cm}^{2}

8 0
3 years ago
Which function corresponds to the table? Bro i need help ngl please help me
34kurt
It would be B:) I hope that helped
3 0
3 years ago
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Help asap !<br><br> -100x - 100 = 0<br> -100x = ?<br> x = ?
marin [14]

Answer:

-100x = 10 x = 1

Step-by-step explanation:

I did the math and this is what I got

6 0
3 years ago
The depth of a lake in Lexington changes over time due to rainfall and evaporation. A few months ago, the depth was 1,300 feet.
SVETLANKA909090 [29]

Answer:

The Depth of the lake had increased by 19%.

Step-by-step explanation:

Given:

Depth of lake few months ago = 1300 ft

depth of lake currently = 1547 ft

We need to find the percent of increase in depth of lake.

Solution:

First we will find the increase in depth of lake.

Increase in depth of lake can be calculated by subtracting Depth of lake few months ago from depth of lake currently.

framing in equation form we get;

increase in depth of lake = 1547-1300= 247\ ft

Now to find the percent of increase in depth of lake we will divide  increase in depth of lake from Depth of lake few months ago and then multiply by 100.

framing in equation form we get;

percent of increase in depth of lake = \frac{247}{1300}\times 100 =  19\%

Hence the Depth of the lake had increased by 19%.

6 0
3 years ago
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