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Dimas [21]
2 years ago
9

PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA 40 POINTS* DONT SKIP :(( .!

Mathematics
1 answer:
UNO [17]2 years ago
6 0

Answer:

D ez

Step-by-step explanation:

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3. f(x) = x - 3<br> find the inverse
nika2105 [10]

Answer:

f(-x)=-x-3

f(x^-1)=(1/x) -3

Step-by-step explanation:

6 0
3 years ago
Simplify (√3 − √7)^2
Alika [10]

Answer: 10 - 2√21

Step-by-step explanation: I simplified your question by using an online calculator. :)

3 0
3 years ago
according to the fundemental theorem of algebra, how many roots exist for the polynomial function? f(x) = (x^3-3x+1)^2
Svetradugi [14.3K]

Answer:

6

Step-by-step explanation:

First, we can expand the function to get its expanded form and to figure out what degree it is. For a polynomial function with one variable, the degree is the largest exponent value (once fully expanded/simplified) of the entire function that is connected to a variable. For example, x²+1 has a degree of 2, as 2 is the largest exponent value connected to a variable. Similarly, x³+2^5 has a degree of 2 as 5 is not an exponent value connected to a variable.

Expanding, we get

(x³-3x+1)²  = (x³-3x+1)(x³-3x+1)

= x^6 - 3x^4 +x³ - 3x^4 +9x²-3x + x³-3x+1

= x^6 - 6x^4 + 2x³ +9x²-6x + 1

In this function, the largest exponential value connected to the variable, x, is 6. Therefore, this is to the 6th degree. The fundamental theorem of algebra states that a polynomial of degree n has n roots, and as this is of degree 6, this has 6 roots

3 0
3 years ago
Find the value of x. <br> Show work.
ivanzaharov [21]

Answer:

x=8

Step-by-step explanation:

The two angles are alternate interior angles. This means that they are equal to each other.

8x-12=3x+28

5x=40

x=8

6 0
2 years ago
I need help writing the first 5 terms of the sequence!
Angelina_Jolie [31]

The first five terms of the sequence are 1, 4, 7, 10, 13.

Solution:

Given data:

a_{1}=1

a_{n}=a_{n-1}+3

General term of the arithmetic sequence.

a_{n}=a_{n-1}+d, where d is the common difference.

d = 3

a_{n}=a_{n-1}+3

Put n = 2 in a_{n}=a_{n-1}+3, we get

a_{2}=a_1+3

a_{2}=1+3

a_2=4

Put n = 3 in a_{n}=a_{n-1}+3, we get

a_{3}=a_2+3

a_{3}=4+3

a_3=7

Put n = 4 in a_{n}=a_{n-1}+3, we get

a_{4}=a_3+3

a_{4}=7+3

a_4=10

Put n = 5 in a_{n}=a_{n-1}+3, we get

a_{5}=a_4+3

a_{5}=10+3

a_5=13

The first five terms of the sequence are 1, 4, 7, 10, 13.

3 0
3 years ago
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