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Brums [2.3K]
2 years ago
8

jayce runs 2 1/2 miles on monday. Each day after that, he runs the same 1 1/3 mile route every morning. His goal is to run at le

ast 6 miles by the end of the week. Which inequality represents the least number of days after monday that jayce needs to run to reach his goal?
Mathematics
1 answer:
PtichkaEL [24]2 years ago
3 0

Answer:

Step-by-step explanation:

6 < 2 1/2 + 1 1/3R

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I'm not really sure but it's 30% yellow and 15% green soo or it is 45% or 15% but idk (i don't know if i helped you but that's what I try to do.

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Mikey has two mice that were about the same age and weight Mikey fed each of the 2 mice a different feed for a month. He measure
Nadusha1986 [10]
The following is the rest of the question:
------------------------------------------------------
Mikey's results showed that although both mice gained weight over the month, mouse 2 gained more weight than mouse 1.Which graph below best shows these results?
The complete figure is attached
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Solution:
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Graph (1)⇒⇒⇒ mouse 2 has constant weight and mouse 1 gained weight

Graph (3)⇒⇒⇒ mouse 2 has did not gain weight and mouse 1 gained weight

∴ Graph (1) and (3) are incorrect because both mice gained weight .

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So, the correct answer is graph (2)







5 0
3 years ago
Read 2 more answers
Find the lateral surface area of the triangular prism shown below.
guajiro [1.7K]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
For the equation, complete the given ordered pairs.<br> 3x - y = 7
Mandarinka [93]

3x-y=7

3x-y-7=7-7

3x-y-7=0

4 0
3 years ago
For the following parameterized​ curve, find the unit tangent vector T​(t) at the given value of t. r​(t) = &lt; 8 t,10,3 sine 2
san4es73 [151]

Answer:

The tangent vector for t = 0 is:

\vec T (t) = \left \langle \frac{8}{10}, 0, \frac{6}{10}   \right\rangle

Step-by-step explanation:

The function to be used is \vec r(t) = \langle 8\cdot t, 10, 3\cdot \sin (2\cdot t)\rangle

The unit tangent vector is the gradient of \vec r (t) divided by its norm, that is:

\vec T (t) =  \frac{\vec \nabla r (t)}{\|\vec \nabla r (t)\|}

Where \vec \nabla is the gradient operator, whose definition is:

\vec \nabla f (x_{1}, x_{2},...,x_{n}) = \left\langle \frac{\partial f}{\partial x_{1}}, \frac{\partial f}{\partial x_{2}},...,\frac{\partial f}{\partial x_{n}} \right\rangle

The components of the gradient function of \vec r(t) are, respectively:

\frac{\partial r}{\partial x_{1}} = 8, \frac{\partial r}{\partial x_{2}} = 0 and \frac{\partial r}{\partial x_{3}} = 6 \cdot \cos (2\cdot t)

For t = 0:

\frac{\partial r}{\partial x_{1}} = 8, \frac{\partial r}{\partial x_{2}} = 0 and \frac{\partial r}{\partial x_{3}} = 6

The norm of the gradient function of \vec r (t) is:

\| \vec \nabla r(t) \| = \sqrt{8^{2}+0^{2}+ [6\cdot \cos (2\cdot t)]^{2}}

\| \vec \nabla r(t) \| = \sqrt{64 + 36\cdot \cos^{2} (2\cdot t)}

For t = 0:

\| \vec r(t) \| = 10

The tangent vector for t = 0 is:

\vec T (t) = \left \langle \frac{8}{10}, 0, \frac{6}{10}   \right\rangle

8 0
3 years ago
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