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Nezavi [6.7K]
2 years ago
5

Order the steps to solve -3x + 2.4=19.2

Mathematics
2 answers:
Anna007 [38]2 years ago
8 0

Answer: It's False.

Step-by-step explanation:

Step by step explanation below!

goldfiish [28.3K]2 years ago
8 0

Answer:

x = -5.6

Step-by-step explanation:

-3x = 16.8

-3x/-3 = 16.8/-3

x = -5.6

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Abscissa is:
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Answer:

The first number (or x value) of an ordered pair.

Step-by-step explanation:

Abscissa is the first number (or x value) of an ordered pair.

A coordinate plane is a way of locating points in a plane that consists of a horizontal and a vertical number line intersecting at the zeros.

Coordinates are an ordered pair, (x, y), that describes the location of a point in the coordinate plane.

Ordinate is the second number (or y value) of an ordered pair.

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4 0
3 years ago
Use the quadratic formula to write a quadratic equation that has the solutions x=-4 ± 2/6.
yKpoI14uk [10]

Step-by-step explanation:

general formula

x²-(a+b)x+(ab)

where a is alpha

and b is beta

x=-4+2/6 or x=-4-2/6

x=-1/3 or x=-1

a+b=-1/3 + -1 =-4/3

ab= -1/3 x -1 =1/3

quadratic equation

x²-(-4/3)x + 1/3=0

x² + 4/3x + 1/3=0

multiply through by 3

3x² +4x +1=0

3 0
2 years ago
Read 2 more answers
M angle a=40° then m angle b=?​
grigory [225]

Answer:

not enough info

Step-by-step explanation:

5 0
3 years ago
How are the distance formula and the pythagorean theorem related to one another?
stira [4]
They are the same because the distance formula depends on a right triangle relationship between x and y, where as the right triangle has the same relationship with x being one leg of the right triangle and y the other leg of the right triangle
3 0
3 years ago
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Find the length of the radius of the circle whose perimeter is xcm and the area is
Jobisdone [24]

\bf \stackrel{\textit{perimeter}}{\textit{circumference}}\textit{ of a circle}\\\\ C = 2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=x \end{cases}\implies x = 2\pi r\implies \boxed{\cfrac{x}{2\pi }=r} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ A=x \end{cases}\implies x = \pi \left( \boxed{\cfrac{x}{2\pi }} \right)^2\implies x = \pi \cdot \cfrac{x^2}{2^2\pi^2}

\bf x = \cfrac{x^2}{4\pi }\implies 4\pi x = x^2\implies \cfrac{4\pi x}{x}=x\implies \blacktriangleright 4\pi = x\blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{since the radius is}}{r = \cfrac{x}{2\pi }}\implies r =\cfrac{4\pi }{2\pi }\implies \blacktriangleright r = 2\blacktriangleleft

6 0
4 years ago
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