Since there is no repetition allowed, there are 10 possibilities for the 1st digit, 9 for the 2nd, 8 for the 3rd, and 7 for the 4th. This gives a total of (10)(9)(8)(7) = 5040 four-digit codes.
For all odd digits to be used, there are 5 possibilities for the 1st digit (1,3,5,7,9), 4 for the 2nd, 3 for the 3rd, 2 for the 4th. This gives a total of (5)(4)(3)(2) = 120 codes that only use odd digits.
Therefore there are 5040 - 120 = 4920 codes that do not consist of all odd digits. The probability is 4920/5040 = 41/42.
Answer:
360 radical 2 or 509.11688
Step-by-step explanation:
simplify the radicals
12 =2 radical 3
calculate the products
10* 2 radical 3 * 6 radical 6
= 120 radical 18
again simplify
360 radical 2
Answer:
x ≥ -0.75
Step-by-step explanation:
3.75 - 3x ≤ 6
Subtract 3.75 on both sides.
- 3x ≤ 6 - 3.75
- 3x ≤ 2.25
Divide both sides with -3.
x ≥ 2.25/-3
x ≥ -0.75
I believe the answer is C
Answer:
1.3888888888889 mps
Step-by-step explanation:
1 kph = 0.27777777777778 mps, so just multiply that by 5.
