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nevsk [136]
3 years ago
5

I think of a number. If I subtract 9 from it and multiply this difference by 4, the

Mathematics
2 answers:
Zepler [3.9K]3 years ago
4 0

Answer:

41

Step-by-step explanation:

Let n be the number

Subtract 9

n-9

Multiply this by 4

4(n-9)

The result is 128

4(n-9)=128

To find the number divide each side by 4

4(n-9)/4=128/4

n-9 = 32

Add 9 to each side

n-9+9 = 32+9

n = 41

dybincka [34]3 years ago
3 0

Answer:

you were thinking of 41

Step-by-step explanation:

(x-9)*4=128

(x-9)=128/4

(x-9)=32

x=32+9

x=41

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The perimeter of a Balcony is 26 ft it is 4 ft wide how long is it?
Dmitrij [34]

Answer:

30ft

Step-by-step explanation:

if you add 26 and 4, you'll get an answer of 40

8 0
3 years ago
Given f(x) = –7x + 9 and h(x) = –5(–7x + 9), what are the slope and y-intercept of the graph of function h?
taurus [48]

The Slope of f(x) = –7x + 9  is (-7)

The slope of  h(x) = –5(–7x + 9) is (35)

The y-int of h(x) is (-45).

4 0
4 years ago
Read 2 more answers
Brianna deposited $680 into a savings account that pays simple and your interest rate of 1.29% how much interest will she earn a
noname [10]
The answer is b just take the decimal off and subtract
8 0
3 years ago
17.
IrinaVladis [17]

Answer:

$32 + $0.25x < $50

Step-by-step explanation:

1.he buy a backpack for $32

2. he buys x amount of pencils. Each pencil cost 0.25. ($0.25x)

3. all of that is less than(<) $50

4 0
3 years ago
A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y = 5 − x 2 . What are the dimensions
kherson [118]

Answer:

A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola

y=5−x^2. What are the dimensions of such a rectangle with the greatest possible area?

Width =

Height =

Width =√10 and Height = \frac{10}{4}

Step-by-step explanation:

Let the coordinates of the vertices of the rectangle which lie on the given parabola y = 5 - x² ........ (1)

are (h,k) and (-h,k).

Hence, the area of the rectangle will be (h + h) × k

Therefore, A = h²k ..... (2).

Now, from equation (1) we can write k = 5 - h² ....... (3)

So, from equation (2), we can write

A =h^{2} [5-h^{2} ]=5h^{2} -h^{4}

For, A to be greatest ,

\frac{dA}{dh} =0 = 10h-4h^{3}

⇒ h[10-4h^{2} ]=0

⇒ h^{2} =\frac{10}{4} {Since, h≠ 0}

⇒ h = ±\frac{\sqrt{10} }{2}

Therefore, from equation (3), k = 5 - h²

⇒ k=5-\frac{10}{4} =\frac{10}{4}

Hence,

Width = 2h =√10 and

Height = k =\frac{10}{4}.

8 0
3 years ago
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