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Pachacha [2.7K]
2 years ago
12

HELPPP LAST ATTEMPT!!

Mathematics
2 answers:
dedylja [7]2 years ago
6 0

Answer:

B' (-1,-5)

Step-by-step explanation:

When it is reflected over the y-axis, the y coordinate stays the same but the x coordinate inverses. In this situation since the x in point B is a positive, the x in point B' will be a negative.

Alecsey [184]2 years ago
3 0
(-1,5)

since it’s being translated over the y axis the only coordinate that’s changing would be the x coordinate. when it’s translated over it would be the opposite to the original point. (positive original point would become a negative point after translated)
hope this helps!
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The floor of a round hut has a diameter of 4 meters. What is the floor's circumference? Use 3.14 for ​.
7nadin3 [17]

Answer:

12.56

Step-by-step explanation:

C= 2 x 3.14 x 2

(the other 2 is half of the circumference)

3 0
3 years ago
Help fast question 1 and 2 is it c and then b for 1 and 2 will give brainliest
myrzilka [38]
For question 1 the answer is B.

for question 2 the answer is C.
3 0
3 years ago
Cot^2x csc^2x + 2 csc^2x –cot^2 = 2
kow [346]

Answer:

x = π/2 + πk

Step-by-step explanation:

cot² x csc² x + 2 csc² x − cot² x = 2

Multiply both sides by sin² x:

cot² x + 2 − cos² x = 2 sin² x

Add cos² x to both sides:

cot² x + 2 = 2 sin² x + cos² x

Pythagorean identity:

cot² x + 2 = sin² x + 1

Subtract 1 from both sides:

cot² x + 1 = sin² x

Pythagorean identity:

csc² x = sin² x

Multiply both sides by sin² x:

1 = sin⁴ x

Take the fourth root:

sin x = ±1

Solve for x:

x = π/2 + 2πk, 3π/2 + 2πk

Which simplifies to:

x = π/2 + πk

4 0
3 years ago
Plz help me solve these problems
leva [86]

Answer: <em><u>CAN YOU PLS MARK AS BRAINLIEST??</u></em>

a.x=11/4

b.x=6

c.x=21/2

d.x=0

Step-by-step explanation:

-2+3x+x=9-x

-2+3x+x=9

4x=9+2

4x=11

x=11/4

when you move a numerator to the other side it becomes a denominator

x+2=3/4x6

x+2=3/24

x=8-2

x=6

5-2x-12=14

2x=14-5+12

2x=21

x=21/2

1/2x=-3-1/2x+4-1

1/2x+1/2x=-3+4-1

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6 0
3 years ago
The endurance of both track athletes and gymnasts is recorded in terms of maximum volume of oxygen and is measured in milliliter
Olin [163]
The mean of the track athletes is given by
\frac{89.2+45.3+89.1+57.3+61.5+80.1+47.2}{7}=67.1

The mean of the gymnasts is given by
\frac{72.1+78.5+66.2+47.3+63.1+89.3+65.3}{7}=68.8

The difference in mean is given by
68.8-67.1=1.73 (rounded to one decimal place)

4 0
3 years ago
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