Question

Which products result in a difference of squares? select three options. (x minus y)(y minus x) (6 minus y)(6 minus y) (3 x z)(negative 3 x z) (y squared minus x y)(y squared x y) (64 y squared x squared)(negative x squared 64 y squared)

Answer 1

The three (3) products that resulted in a difference of squares are:

• (3 + xz)(-3 + xz)

• (y² - xy)(y² + xy)

• (64y² + x²)(-x² + 64y²)

How to determine the difference of squares?

In Mathematics, the standard form for a difference of two (2) squares is given by a² - b² = (a + b)(a - b).

(3 + xz)(-3 + xz) = (3 + xz)(xz -3)

(3 + xz)(xz -3) = 3xz - 9 + x²z² - 3xz.

(3 + xz)(xz -3) = x²z² - 9

Therefore, x²z² - 9 ≡ a² - b²

(y² - xy)(y² + xy) = y⁴ + xy³ - xy³ - x²y²

(y² - xy)(y² + xy) = y⁴ - x²y²

Therefore, y⁴ - x²y² ≡ a² - b².

(64y² + x²)(-x² + 64y²) = (64y² + x²)(64y² - x²)

(64y² + x²)(-x² + 64y²) = 4096y⁴- 64y²x² + 64y²x² - x⁴

(64y² + x²)(-x² + 64y²) = 4096y⁴ - x⁴

Therefore, 4096y⁴ - x⁴ ≡ a² - b².

Read more on difference of squares here: brainly.com/question/24673551