The three (3) products that resulted in a difference of squares are:
<h3>How to determine the
difference of squares?</h3>
In Mathematics, the standard form for a difference of two (2) squares is given by a² - b² = (a + b)(a - b).
(3 + xz)(-3 + xz) = (3 + xz)(xz -3)
(3 + xz)(xz -3) = 3xz - 9 + x²z² - 3xz.
(3 + xz)(xz -3) = x²z² - 9
Therefore, x²z² - 9 ≡ a² - b²
(y² - xy)(y² + xy) = y⁴ + xy³ - xy³ - x²y²
(y² - xy)(y² + xy) = y⁴ - x²y²
Therefore, y⁴ - x²y² ≡ a² - b².
(64y² + x²)(-x² + 64y²) = (64y² + x²)(64y² - x²)
(64y² + x²)(-x² + 64y²) = 4096y⁴- 64y²x² + 64y²x² - x⁴
(64y² + x²)(-x² + 64y²) = 4096y⁴ - x⁴
Therefore, 4096y⁴ - x⁴ ≡ a² - b².
Read more on difference of squares here: brainly.com/question/24673551
