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RSB [31]
2 years ago
5

Triangle A′B′C′ is the image of triangle ABC after a dilation.

Mathematics
1 answer:
IceJOKER [234]2 years ago
7 0

Answer:

3

Step-by-step explanation:

could the length of the first triangle to the length of the second triangle

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Answer:

x=\frac{(a^2+ab)}{a-b}

Step-by-step explanation:

So we want to make x the subject of the formula:

a(x-b)=a^2+bx

First, distribute the left side:

a(x)-a(b)=a^2+bx\\ax-ab=a^2+bx

Combine all the terms with x with it on one side. To do this, first subtract bx from both sides. The right side cancels:

(ax-ab)-bx=(a^2+bx)-bx\\ax-ab-bx=a^2

Remove the -ab from the left. Add ab to both sides. The left side cancels:

(ax-ab-bx)+ab=a^2+ab\\ax-bx=a^2+ab

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ax-bx=a^2+ab\\x(a-b)=a^2+ab

Divide both sides by (a-b). The left side cancels:

\frac{(x(a-b))}{a-b}=\frac{(a^2+ab)}{a-b}  \\x=\frac{(a^2+ab)}{a-b}

Therefore:

x=\frac{(a^2+ab)}{a-b}

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