Answer:
The quadratic equation is x^2-2x-4
Step-by-step explanation:
We want to know the equation that has the solution below;
x = 1 ± √5
This means x = 1 + √5 or 1 - √5
The equation would thus be;
(x-1-√5)(x-1+ √5)
= x(x-1+ √5)-1(x-1+ √5)-√5(x-1+ √5)
Opening the brackets we have ;
x^2-x+ √5x-x + 1 -√5-√5x+ √5-5
collecting like terms we have;
x^2-2x+1-5
= x^2-2x-4
Answer:
#5: (6,6) and #6: (6,4)
And I have no idea with the 2nd part of each questions.
Because d actually collects data about what the people want.
The first thing I'd do is put this equation into standard slope - intercept form.
12x - 5y = 2 Subtract 12x from each side
-5y = -12x + 2 Divide each side by -5 to isolate the <em>y
</em><em />y = 12/5(x) - 2/5
The slope for this equation is 12/5, so we just take that and plug it into the slope - intercept equation with the given points (2, 3)
y = mx + b Fill in the variables
3 = 12/5(2) + b Simplify
3 = 24/5 + b Subtract 24/5 (or 4 4/5) from each side
-9/5 = b
Now we just fill in the correct variables (m and b) in the equation to have our final answer.
y = 12/5x - 9/5
