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s344n2d4d5 [400]
2 years ago
7

Which is a stretch of an exponential decay function?

Mathematics
1 answer:
Marta_Voda [28]2 years ago
4 0

Answer:

The correct option is C. The function f(x)=\frac{5}{4}(\frac{4}{5})^x is a stretch of an exponential decay function.

Step-by-step explanation:

The general form of an exponential function is

f(x)=ab^x

where, a is the initial value and b is the growth factor.

If b<1, then it represents a decay function and if b>1, then it represents a growth function.

Let k be a stretch and compression factor.

g(x)=kf(x)

If k<1, then it represents vertical compression and if k>1, then it represents vertical stretch.

In third function

f(x)=\frac{5}{4}(\frac{4}{5})^x

k > 1

b < 1

Therefore the function f(x)=\frac{5}{4}(\frac{4}{5})^x is a stretch of an exponential decay function.

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