You need to show me the model, so I can answer the question.
Answer:

Step-by-step explanation:
so you already have the formula, which is
![\sqrt[3]{ \frac{3v}{4\pi} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3v%7D%7B4%5Cpi%7D%20%7D%20)
the v represents Volume.
and 3v would be 3×volume.
![\sqrt[3]{ \frac{3 \times 1000}{4 \times \pi} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3%20%5Ctimes%201000%7D%7B4%20%5Ctimes%20%5Cpi%7D%20%7D%20)
![\sqrt[3]{ \frac{3000}{12.56637061} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3000%7D%7B12.56637061%7D%20%7D%20)
![\sqrt[3]{238.7324147 }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B238.7324147%20%7D%20)

to the nearest tenth place.

Given:
The table of values is
Number of Students : 7 14 21 28
Number of Textbooks : 35 70 105 140
To find:
The rate of change and showing that the ratios of the two quantities are proportional and equivalent to the unit rate.
Solution:
The ratio of number of textbooks to number of students are




All the ratios of the two quantities are proportional and equivalent to the unit rate.
Let y be the number of textbooks and x be the number of students, then

Here, k=5.


Hence the rate of change is constant that is 5.
Hello bestie I cannot help you