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3 years ago

Can someone help me solve this and explain how to solve if possible please?

Mathematics

1 answer:

DIA [1.3K]3 years ago

4 0

The length of road is the range and the time
in days is the domain. Any measure of time, like years, days, minutes will always be the independent variable, D. What does it mean by set of values?

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What is the slope of -y=-x+6

Katarina [22]

Answer:

m = 1
b = -6

Step-by-step explanation:

We know that:

-y = -x + 6
y = mx + b

First, we need to change the 'y' sign.

=> -y = -x + 6
=> y = x - 6

Now, let's compare both of the equations to find slope.

=> (y = x - 6) = (y = mx + b)

We can see that the slope is 1 and the y-intercept is -6.

Conclusion:

Therefore:

m = 1
b = -6

Hoped this helped.

4 0

2 years ago

Jacoby made and sold x candy bars in one week. His profit, P, in dollars is calculated using the formula P = R-C

Mashutka [201]

Answer:ion even know cus i just want the points

Step-by-step explanation:

5 0

3 years ago

Cramer's rule:

Irina18 [472]

Answer:

$a. \quad\dfrac{\left|\begin{array}{cc}148&14\\246&5\end{array}\right|}{\left|\begin{array}{cc}-2&14\\3&5\end{array}\right|}=52$

Step-by-step explanation:

To find the value of x, Cramer's rule says you replace the x-coefficients with the equation constants to form the matrix whose determinant is the numerator of the fraction. The denominator is the determinant of the matrix of coefficients. The equation constants are 148 and 246, so you expect to find those in the first column of the numerator (answer choices A and C).

$\dfrac{\left|\begin{array}{cc}148&14\\246&5\end{array}\right|}{\left|\begin{array}{cc}-2&14\\3&5\end{array}\right|}=\dfrac{-2704}{-52}=52$

The calculation is carried out correctly only in answer choice A.

5 0

3 years ago

18 PTS! From the equation below, identify the slope and a point on the line. y−3=−2(x+1)

omeli [17]

ANSWER:

The slope of the given equation is -2 and a point on the given line is (-1, 3)

SOLUTION:

Given, linear equation in two variables is y – 3 = -2(x + 1) ----- eqn (1)

We need to find the slope of the given equation and a point through which the given line passes.

Given equation is in the form of point slope form .i.e $\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right)$ --- eqn 2

where,"m" is the slope of the line

$\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)$ is point on that line.

Now, by comparing (1) and (2)

m = -2

$x_{1}=-1$

$y_{1}=3$

so, the slope of the given equation is -2 and a point on the given line is (-1, 3)

7 0

3 years ago

I need help solving quadratics

jolli1 [7]

Quadratic equations are the equations that can be re arranged in the linear or the standard form.

Explanation:

In algebra, a quadratic equation is any condition that can be adjusted in standard structure as where x speaks to an unknown, and a, b, and c speak to known numbers, where a ≠ 0. On the off chance that a = 0, at that point the condition is straight, not quadratic, as there is no term.

Quadratic equations are really utilized in regular day to day existence, as while ascertaining regions, deciding an item's benefit or figuring the speed of an article. Quadratic conditions allude to conditions with in any event one squared variable, with the most standard structure being ax² + bx + c = 0.

8 0

3 years ago