Remark
There's a lot you don't know here. Are DE and GF parallel? Is B a right angle? You can't assume that it is. The safest way to proceed is to give x in terms of 58 and B. You might get an answer that gives you something like 32 but I don't think you can say that unless you are told somewhere that ABC is a right angle triangle with the right angle at B.
So what to do.
<BAC = 58o That's because <BAC = <IAK They vertically opposite.
<ABC + <BAC + <ACB = 180o All triangles have 180o
<ACB = 180 - 58 - <ABC Solve for an unknown angle of a triangle.
<ACB = 122 - <ABC
x = <ACB Vertically opposite angles.
x = 122 - <ABC Answer It's 32 if ABC is a right angle.
You can just use a calculator but when you add the numbers all together you get 323
40°, 60° and 80°
sum the parts of the ratio 2 + 3 + 4 = 9
The sum of the angles in a triangle = 180°
Divide 180 by 9 to find one part of the ratio
= 20° ← 1 part of the ratio
2 parts = 2 × 20 = 40°
3 parts = 3 × 20 = 60°
4 parts = 4 × 20 = 80°
The angles in the triangle are 40°, 60° and 80°
20.5 is the IQR of the given set of numbers.