Answer:
1.60934 per hour
please mark me brainliest
P(x) = x^2 - 1
q(x) = 5(x - 1)
(p - q)(x) = (x^2 - 1) - 5(x - 1)
H=+15 m
v=+5 m/s
Ball hits the ground when h(t)=-15m
h(t)=-9.8t^2+vt+h
=>
-15=-9.8t^2+5t+15
9.8t^2-5t-30=0
Solve for t, using quadratic formula,
t=-1.513 or t=2.023
reject negative root due to context, so
t=2.023 seconds
2)
h(t)=-16t^2+20t+8
a. height before pitch is when t=0, or h(0)=8
b. highest point reached when h'(t)=-32t+20=0 => t=5/8 seconds
c. highest point is t(5/8)=-16(5/8)^2+20(5/8)+8=47/5=9.4 m
d. ball hits ground when h(t)=0 => solve t for h(t)=0
=> t=-0.3187 seconds or t=1.569 seconds.
Reject negative root to give
time to hit ground = 1.569 since ball was pitched.
Answer:
Values of y in order: 0, 2, 4, 6
Step-by-step explanation:
Hi there!
In the table, the first value of x is -2. To find the value of y for this row of the table, we can use the given equation .
Plug in -2 as the value of x
Therefore, y is 0 when x is -2. (In the table, in the row where x is -2, y would be 0.)
We repeat this process for the rest of the values in the table.
When x=-1:
When x=0:
When x=1:
I hope this helps!