The waiting time at which 10 percent of the people would continue to hold is given as 2.3
<h3>How to solve for the waiting time</h3>
We have to solve for X ~ Exponential(λ).
then E(X) = 1/λ = 3,
= 0.3333
Remember that the cumulative distribution function of X is F(x) = 1 - e^(-λx). ; x is equal to the time in over case
For 10 percent of the people we would have a probability of
10/100 = 0.1
we are to find
P(X ≤ t)
= 1 - e^(0.3333)(t) = 0.1
Our concern is the value of t
Then we take the like terms
1-0.1 = e^(0.3333)(t)
1/0.9 = e^(0.3333)(t)
t = 3 * ln(1/0.9)
= 0.3157
Answer
The answer and procedures of the exercise are attached in the following archives.
Step-by-step explanation:
You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.
Answer:
The answer is marketing intermediary
Explanation:
Jonathan works for a firm that assists companies in promoting, distributing, and selling their products to end consumers. The firm Jonathan works for is a marketing intermediary.
A marketing intermediary links producers to the final consumers. Examples are agents, wholesalers, retailers, distributors etc.
Most producers do not directly sell to their final consumers. These intermediaries help them to achieve their goals
4(x + 1)
Hope I helped!
Let me know if you need anything else!
~ Zoe