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scoray [572]
2 years ago
13

Pls help me with this!

Mathematics
2 answers:
BlackZzzverrR [31]2 years ago
8 0

Answer:

0.69

Step-by-step explanation:

In a right triangle, the cosine of one of the acute angles is the ratio of the adjacent ("next to") side to the hypotenuse.

In this triangle, the side adjacent to angle T has length \sqrt{38}.  Now you need the length of the hypotenuse, <em>ST</em>.  Use the Pythagorean Theorem:

ST^2=(\sqrt{38})^2+(\sqrt{41})^2 \\\\ST^2=38+41\\\\ST=\sqrt{79}

Build the ratio (adjacent) / (hypotenuse) and approximate it with a decimal.

\cos{T}=\frac{\sqrt{38}}{\sqrt{79}} \approx 0.69

Simora [160]2 years ago
5 0

{\large{\red{\mapsto{\maltese{\underline{\green{\boxed{\blue{\underbrace{\overbrace{\pink{\pmb{\bf{Answer:}}}}}}}}}}}}}}

<u>To</u><u> </u><u>find</u><u> </u><u>:</u><u>-</u>

Cos T = ?

<u>Given</u><u> </u><u>:</u><u>-</u>

Perpendicular(P) = RS = √41

Base(B) = RT = √38

<u>Formula</u><u> </u><u>to</u><u> </u><u>be</u><u> </u><u>used</u><u> </u><u>:</u><u>-</u>

<em>We</em><em> </em><em>will</em><em> </em><em>use</em><em> </em><em>here</em><em> </em><em>a</em><em> </em><em>trignometry</em><em> </em><em>formula</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>hypotenuse</em><em> </em>(H) <em>which</em><em> </em><em>is</em><em> </em><u>ST</u>.

(hypotenuse)² = (perpendicular)² + (base)²

\cos(A)  =  \frac{base}{hypotenuse}

<u>Solution</u><u>:</u><u>-</u>

H² = P² + B²

H² = (√41)² + (√38)²

H² = 41 + 38

H² = 79

H = √79

\cos(T)  =  \frac{B}{H}  \\  \cos(T)  =  \frac{ \sqrt{38} }{ \sqrt{79} }  \\  \cos(T)  =  \frac{6.17}{8.89}  \\  \cos(T)  = 0.69

<u>Result</u><u> </u><u>:</u><u>-</u>

The value of cos(T) is 0.69.

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Answered by GAUTHMATH

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Step-by-step explanation:

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