Answer:
51 were the total number of the tickets sold at a school carnival were early-admission tickets.
Step-by-step explanation:
Total number of tickets sold by = 100
Let be the early-admission tickets sold by the school.
As 51% of the tickets sold at a school carnival were early-admission tickets.
so
Therefore, 51 were the total number of the tickets sold at a school carnival were early-admission tickets.
a) Z-score for Patrisse test grade is 0.7288
b) z-score for Makayla test grade is -0.7441
c) Patrisse did better.
<h3>What is z- score?</h3>
A Z-score is a numerical measurement that describes a value's relationship to the mean of a group of values.
Z-score for Patrisse test grade.
X= 81.4, = 72.8,
= 11.8
Z= x- /
Z= 81.4 - 72.8/ 11.8
Z= 0.7288
Now, z-score for Makayla test grade.
X= 60.6, = 67,
= 8.6
Z= x- /
Z= 60.6 - 67/ 8.6
Z= -0.7441
Hence, Patrisse did better as she had better z- score.
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Answer:
Step-by-step explanation:
The pdf of the number of cheesecakes that they sell in a given day: by a bakery are as follows:
X 0 5 10 15 20
P 0.25 0.47 0.12 k 0.15
Use total prob =1, to find k .
k = 0.01
a) the probability of selling 15 cheesecakes in a given day = 0.01
b. What is the probability of selling at least 10 cheesecakes =P(X≥10)
= 0.28
c. the probability of selling 5 or 15 chassescakes P(5)++P(15)=0.48
d. the probaility of selling 25 cheesecakes = 0
e. Give the expected number of cheesecakes sold in a day using the discrete probability distribution?
=
f. the probability of selling at most 10 cheesecakes
=P(X≤10)
= 0.84