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vodomira [7]
2 years ago
13

Write an equation of the line in slope-intercept form (-3,3) (0,-1)

Mathematics
1 answer:
Vesnalui [34]2 years ago
3 0
Y= 4/3x -1 use y2-y1 over x2-x1

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The diagonals of a quadrilateral must be bisect each other and be perpendicular to gurarantee that the quadrilateral is a parrel
morpeh [17]

Answer:

False

Step-by-step explanation:

A quadrilateral is a closed geometrical figure that have four sides and four vertices. Thus the following includes in a quadrilateral : parallelogram, square, rhombus, rectangle and trapezium.

If the diagonals of the quadrilateral bisects each other and are perpendicular to each other, then the quadrilateral forms a rhombus.

Hence the answer is FALSE.

4 0
3 years ago
10 to the 5th power plus 10 to the -1 power
Serggg [28]
1000000+1/10. There are no rules for when you add the powers.
8 0
3 years ago
An eraser is in the shape of a triangular prism. Its dimensions are shown in the diagram. What is surface area of the
Colt1911 [192]

Answer:

6000 square millimeters

Step-by-step explanation:

Side length of the slanting side can be calculated using the Pythagorean theorem,

L = sqrt(30^2+40^2) = 50

sufrace area of a triangular prism

= surface area of the end sections + the surface area of the three side faces

= 2*(30*40/2) + 40*(30+40+50)

= 1200 + 4800

= 6000 mm^2

4 0
3 years ago
Read 2 more answers
Sam brought brushes for $8,a palette for $5,and oil paints for $15.He paid 29.82 in all.What sale-tax rate did Sam pay?
sertanlavr [38]
8+5+15=28 
29.82-28=    1.82 or 182%



5 0
3 years ago
A car starts with a dull tank of gas. After driving around 5he city, 1/7 of the gas has been used. With the rest of the gas in t
Sati [7]

Answer:

\frac{2}{7}

Step-by-step explanation:

Given:

A car starts with a dull tank of gas

1/7 of the gas has been used around the city.

With the rest of the gas in the car, the car can travel to and from Ottawa three times.

Question asked:

What fractions of a tank of gas does each complete trip to Ottawa use?

Solution:

Fuel used around the city = \frac{1}{7}

Remaining fuel after driving around the city = 1 - \frac{1}{7}

                                                                         =    \frac{7 - 1}{7}  = \frac{6}{7}

According to question:

As from the rest of the gas in the car that is \frac{6}{7}, the car can complete 3 trip to Ottawa  which means,

By unitary method:

The car can complete 3 trip by using = \frac{6}{7} tank of gas.

The car can complete 1 trip by using =  \frac{6}{7} \div 3

                                                             =\frac{6}{7} \times\frac{1}{3}

                                                             =  \frac{6}{21}

                                                             = \frac{2}{7} tank of gas

Thus, \frac{2}{7} tank of gas used for each complete trip to Ottawa.

5 0
3 years ago
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