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Natali [406]
2 years ago
10

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER

Mathematics
1 answer:
WINSTONCH [101]2 years ago
6 0

c = 39

hope it helps...!!!

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Evaluate −b2−2bx2−x when x=−2.
Y_Kistochka [10]
The answer...... is 6x+2
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3 years ago
What is the slope of the line shown below?
Harman [31]

Answer:

2

Step-by-step explanation:

Slope is often called rise/run.

This is the amount the line goes upwards, rise, compared to the amount it goes sideways, run.  

Compare the two shown points.  From the left point the the right, the rise is 6, while the run is 3, creating the rise/run of 6/3.  This is simplified to 2.

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2 years ago
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What is the volume of the volume of the following rectangular prism
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2 years ago
7=-5/2 x + b<br>what is the value of b and please explain.​
Talja [164]

Answer:

b = 5/2x + 7

Step-by-step explanation:

b + (-5/2x) = 7

b - 5/2x = 7

b = 5/2x + 7

3 0
2 years ago
A sample of 1500 computer chips revealed that 32% of the chips do not fail in the first 1000 hours of their use. The company's p
Grace [21]

Answer:

Yes, we have sufficient evidence at the 0.02 level to support the company's claim.

Step-by-step explanation:

We are given that a sample of 1500 computer chips revealed that 32% of the chips do not fail in the first 1000 hours of their use. The company's promotional literature claimed that above 29% do not fail in the first 1000 hours of their use.

Let Null Hypothesis, H_0 : p \leq 0.29  {means that less than or equal to 29% do not fail in the first 1000 hours of their use}

Alternate Hypothesis, H_1 : p > 0.29  {means that more than 29% do not fail in the first 1000 hours of their use}

The test statics that will be used here is One-sample proportions test;

          T.S. = \frac{\hat p -p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = proportion of chips that do not fail in the first 1000 hours of their use = 32%

            n = sample of chips = 1500

So, <u>test statistics</u> = \frac{0.32-0.29}{\sqrt{\frac{0.32(1-0.32)}{1500} } }

                              = 2.491

<em>Now, at 0.02 level of significance the z table gives critical value of 2.054. Since our test statistics is more than the critical value of z so we have sufficient evidence to reject null hypothesis as it fall in the rejection region.</em>

Therefore, we conclude that more than 29% do not fail in the first 1000 hours of their use which means we have sufficient evidence at the 0.02 level to support the company's claim.

7 0
3 years ago
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