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RideAnS [48]
3 years ago
14

Which pairs of figures are congruent? Which pairs are similar?

Mathematics
1 answer:
Wittaler [7]3 years ago
4 0

Answer:

1 is congruent, 2 is similar, 3 is similar, and 4 is congruent

Step-by-step explanation:

2 and 3 aren't the same size so they aren't congruent, but the other two are the same size and shape so they are congruent

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A certain organization recommends the use of passwords with the following​ format: vowel commavowel, consonant comma consonant c
zimovet [89]

The password format is = inpray93

vowel , consonant, consonant, consonant, vowel, consonant, number, number.

There are 21 consonants, 5 vowels and 10 number choices (0-9)

Since, there are 21 consonants and repetition is allowed so for 2nd, 3rd, 4th, and 6th positions 21 choices are available. For 1st and 5th positions, 5 choices  are available and for 7th and 8th position there are 10 choices (0 to 9).

Passwords are not case sensitive which means upper case and lower case letters are same.

So, the number of passwords can be =

5\times21\times21\times21\times5\times21\times10\times10

= 486202500

Part (b) question is not given. But it can be opposite to the first part i.e when the password letters are case sensitive.

This means all the letters are different.

So, number of passwords will be =

10\times42\times42\times42\times10\times42\times10\times10

= 31116960000

4 0
3 years ago
Answer question please.?
marin [14]
2. 8 books total 2 books fiction= 2/8 fiction

4. 6 ferns total 2 have been watered= 4/6 havent been 

6. 3/4=6/8 clamshelss
8 0
3 years ago
What sales tax, at the rate of 5% must you pay on the purchase of a computer hard drive that cost $229?
White raven [17]
The answer is $11.45
6 0
3 years ago
A company has 200 machines. Each machine has 129 probability of not working. If you were to pick 40 machines randomly, the proba
alexgriva [62]

The probability that 5 would not be working is 0.18665, the probability that at least one machine would be working is 0.00602 and the probability that all would be working is 1.

Given a company has 200 machines. Each machine has a 12% probability of not working.

If we working pick 40 machines randomly then we have to find the probability that 5 would not be working, the probability that at least one machine would be working, and the probability that all would be working.

So

1) probability that 5 would not be working

C(40,5)·0.12⁵·0.88³⁵= 40!/(5!(40-5)!)·0.12⁵·0.88³⁵

                                ≈ 0.18665

2)  probability that at least one machine would be working

0.88⁴⁰ ≈ 0.00602

3) probability that all would be working

1 - 0.12⁴⁰ ≈ 1.0000

Learn more about probability here: brainly.com/question/24756209

#SPJ10

7 0
2 years ago
Which of the following number is divisible by 5 729, 86, 970, 52
Anni [7]
970 all the others are not
4 0
3 years ago
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