504,047 written in expanded form

Mathematics

1 answer:

Nutka1998 [239]1 year ago

5 0

Answer:

500,000 + 4,000 + 40 + 7

<h2>BRAINLIEST please if this helped!</h2>

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Pls give me the answer! Thanks!

Mademuasel [1]

Answer:

Step-by-step explanation:

7 x 6 = 42 + 9 = 51 + 54 = 105 + 75= 180

6 0

2 years ago

Read 2 more answers

A pool has an area of 1,275 m2 and a width of 25 1/2 m. What is the length of the pool.

lisov135 [29]

Answer:

50m is the length of the pool

Step-by-step explanation:

area= length * width

length= area/ width

1275/ 25.5 = 50

5 0

2 years ago

jenns age is 3 years less than marks age the sum of their ages is 30 let m be marks age find Jenna age

melamori03 [73]

Answer:

you could do 27+x=30

Step-by-step explanation:

7 0

3 years ago

Assume you have such a watch. if a minimum of 18.0% of the original tritium is needed to read the dial in dark places, for how m

laila [671]

Given that the half life of 3H is 12.3 years.

The amount of substance left of a radioactive substance with half life of $t_{ \frac{1}{2} }$ after t years is given by

$N(t)=N_0\left(\frac{1}{2} \right)^{ \frac{t}{t_{\frac{1}{2}} }$

Therefore, the number of years it will take for 18% of the original tritinum to remain is given by

$18 \% = 100 \% \left(\frac{1}{2} \right)^{ \frac{t}{12.3}} \\ \\ \Rightarrow\left(\frac{1}{2} \right)^{ \frac{t}{12.3}} =0.18 \\ \\ \Rightarrow\frac{t}{12.3}\ln\left(\frac{1}{2} \right)=\ln0.18 \\ \\ \Rightarrow\frac{t}{12.3}= \frac{\ln0.18}{\ln\left(\frac{1}{2} \right)} = \frac{-1.715}{-0.6931} =2.474\\ \\ \Rightarrow t=2.474(12.3)=30.4$

Therefore, the number of <span>years that the time could be read at night is 30.4 years.</span>

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3 years ago

What is required to have a legally valid contract?

Olegator [25]

It typically just needs two parts
1) all parties must be in agreement
2) something of value needs to be exchanged. ie. money, a service

3 0

2 years ago