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ZanzabumX [31]
3 years ago
9

Mr. Martin is giving a math test next period. The test, which is worth 100 points, has 29 problems. Each problem is

Mathematics
1 answer:
umka2103 [35]3 years ago
6 0

Answer:

the answer is A. x + y = 29, 5x + 2y = 100

Step-by-step explanation:

just finished the question

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Solve for x. Enter your answer in interval notation using grouping symbols <br> X^2 + 5x &lt; 24
icang [17]
I think the correct answer would be : (-8,3)
I hope this helps !
7 0
3 years ago
The table below shows some inputs and outputs of the invertible function f with domain all real numbers.
Ratling [72]

Answer:

{f}^{ - 1} (f(93)) = 93

f(f(7)) =  - 15

Step-by-step explanation:

A function and its inverse has the following properties

{f}^{ - 1} (f(x)) = x

This implies that;

{f}^{ - 1} (f(93)) = 93

From the table,

f(7) =  - 6

This means that:

f(f(7)) = f( - 6)

f(f(7)) =  - 15

Note that: f(7) means the value of f(x) when x=7.

From the table f(x)=-6 when x=7.

That is why f(7)=-6.

5 0
3 years ago
Write the standard form of the equation of a line if the point on the line nearest to the origin is at (6, 8).
Alchen [17]

Answer:

\large\boxed{y=\dfrac{4}{3}x}

Step-by-step explanation:

The line passes through the origin has an equation y = mx

m - slope

The formula of a slope of a line passes through the origin

and a point (x, y):

m=\dfrac{y}{x}

We have the point (6, 8). Substitute:

m=\dfrac{8}{6}=\dfrac{8:2}{6:2}=\dfrac{4}{3}

Finally:

y=\dfrac{4}{3}x

4 0
3 years ago
Martin was given 10 math problems, and he has answered 7 of them. What percent of the problems does Martin have left to do?
Artyom0805 [142]
Martin still has 30% of the problems left to do.
7 0
4 years ago
Read 2 more answers
The heat developed in an electric wire varies jointly as the wires resistance, the time the current flows, &amp; the square of t
never [62]

Answer:

4 ohms

Step-by-step explanation:

The question is "In two minutes a current of 5 amps develops 1,200 heat units in a wire of 8 ohms resistance. What resistance does a similar wire have, which develops 6,000 heat units with a current of 10 amps in 5 minutes?"

Current, I₁ = 5 A

Heat, Q₁ = 1200 units

Resistance, R₁ = 8 ohms

Time, t₁ = 2 min = 120 s

New heat, Q₂ = 6000 units

Current, I₂ = 10 A

New time, t₂ = 5 min = 300 s

We need to find the new resistance.

Heat developed is given by :

Q=I^2Rt

\dfrac{Q_1}{I_1^2R_1t_1}=\dfrac{Q_2}{I_2^2R_2t_2}\\\\R_2=\dfrac{Q_2\times I_1^2R_1t_1}{Q_1I_2^2t_2}\\\\R_2=\dfrac{6000\times 5^2\times 8\times 120}{1200\times 10^2\times 300}\\\\=4\ \Omega

So, the new resistance is 4 ohms.

5 0
3 years ago
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