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2 years ago

Please help!! Thanks Solve for a. 6a–5=7+8a

Mathematics

2 answers:

IRISSAK [1]2 years ago

6 0

Answer:

-6

Step-by-step explanation:

6a - 5 = 7 + 8a

6a - 8a = 7 + 5

-2a = 12

a = 12/-2

a = -6

Hope it helps:)

Nikitich [7]2 years ago

4 0

A=-6

6a-5=7+8a
Move the terms
6a-8a=7+5
Collect like terms
Calculate
-2a=12
Divide both side
a=-6

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What is the solution to the system below? <br> -4x + 5y = 27<br> x - 6y = -2

daser333 [38]

Answer:

(x,y)=(-8,-1)

Step-by-step explanation:

(2) rearrange

x=-2+6y

-4(-2+6y)+5y=27

8-24y+5y=27

8-19y=27

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3 0

3 years ago

Choose the fraction that has not been reduced to simplest form 19/3810/1921/3415/18

lozanna [386]

19/38 and 15/18

Explanation:

19/38 can be reduced as there is a factor other than 1 that can divide without a remainder. Factor is 19

It can still be reduced because 19*2 = 38

19/38 = 1/2

10/19 cannot be reduced as there is no factor other than one to divide without a remainder

21/34 cannot be reduced as there is no factor other than one to divide without a remainder

15/18 can be reduced as there is a factor other than 1 that can divide without a remainder.

The factor is 3

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Fraction that has not been reduced to simplest form are 19/38 and 15/18

5 0

1 year ago

PLEASE HELP ME 40 PTS!!!!!!

SSSSS [86.1K]

Answer:

The sequence converges to infinity.

Step-by-step explanation:

$a_n = \frac{n^3 - n}{n^2 + 5n}\\\\ \lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{n^3 - n}{n^2 + 5n}$

$= \lim_{n \to \infty} \frac{n(n^2 - 1)}{n(n + 5)} \\\\= \lim_{n \to \infty} \frac{(n^2 - 1)}{(n + 5)}\\\\= \lim_{n \to \infty} \frac{n(n - \frac{1}{n})}{n(1 + \frac{5}{n})}\\\\= \lim_{n \to \infty} \frac{(n - \frac{1}{n})}{(1 + \frac{5}{n})}$

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$numerator = \lim_{n \to \infty} n - \frac{1}{n} = \infty$

Therefore,

$\lim_{n \to \infty} a_n = \frac{ \infty}{1} = \infty$

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3 years ago

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dem82 [27]

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4 years ago

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fredd [130]

Answer:

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3 years ago

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