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Viktor [21]
3 years ago
5

Which equation is represented by the graph below

Mathematics
1 answer:
Serga [27]3 years ago
7 0

Answer:

y=in ×-3

it's the answer

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How to solve -5+7|5x-3|= 37
nata0808 [166]

Solve for  x  by simplifying both sides of the equation, then isolating the variable.

Exact Form would be or look like

x=9/5, -3/5

5 0
3 years ago
Read 2 more answers
1) Solve for Side A.<br><br> 2) Solve for Angle B.
avanturin [10]

Answer:

solution given;

let

AB=a

AC=b=30ft

AB=c=20ft

<A=115°

By using Cosine rule.

a²=b²+c²-2bc cos angle

a²=30²+20²-2*30*20 Cos 115°

a²=1807.1419

a=√[1807.1419]

a=42.51

Side A is 42.51ft.

Again

Cos B=\frac{a²+c²-b²}{2ac}

Cos B=\frac{42.51²+20²-30²}{2*42.51*20}

Cos B=0.7687

<B=Cos -¹(0.7687)

<B=39.46°

Angle B is 39.46

4 0
3 years ago
Read 2 more answers
Someone plz help me giving brainliest
sukhopar [10]

Answer:

1/14

Step-by-step explanation:

1 - 5/7 = 7/7 - 5/7 = (7-5)/7

Subtract. 7 - 5 = 2

= 2/7

Now we have to multiply 2/7 and 1/4

We get 2/7 x 1/4 = <em>1/14</em>

7 0
3 years ago
Question 21
RUDIKE [14]

Answer:

y=-2x+1

Step-by-step explanation:

Perpendicular lines have slopes that are negative reciprocals of one another.  slope 1/2 perpendicular will be -2/1=-2

y-5=-2(x-(-2))

y-5=-2(x+2)

y-5=-2x-4

y=-2x-4+5

y=-2x+1

6 0
3 years ago
The heights of women in the USA are normally distributed with a mean of 64 inches and a standard deviation of 3 inches.
Rainbow [258]

Answer:

(a) 0.2061

(b) 0.2514

(c) 0

Step-by-step explanation:

Let <em>X</em> denote the heights of women in the USA.

It is provided that <em>X</em> follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.

(a)

Compute the probability that the sample mean is greater than 63 inches as follows:

P(\bar X>63)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{63-64}{3/\sqrt{6}})\\\\=P(Z>-0.82)\\\\=P(Z

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.

(b)

Compute the probability that a randomly selected woman is taller than 66 inches as follows:

P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-64}{3})\\\\=P(Z>0.67)\\\\=1-P(Z

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.

(c)

Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

P(\bar X>66)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{66-64}{3/\sqrt{100}})\\\\=P(Z>6.67)\\\\\ =0

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.

8 0
3 years ago
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