What is the line of the equation PARALLEL to the line y=3x+4 and through the y-intercept of -6?

Mathematics

2 answers:

Eddi Din [679]2 years ago

7 0

Answer:

y = 3x - 6

Step-by-step explanation:

The line here is parallel

Slope remains the same
Y-intercept is now -6

Equation of line

y = mx + c [where m = slope and c = y-intercept]
y = 3x - 6

DerKrebs [107]2 years ago

6 0

Parallel lines have slopes that are equal to one another.

Slope intercept form is:

y = mx + b (where m = slope and b = y-intercept)

the equation of the 1st line

y = 3x + 4 so it’s slope (m) = 3

the problem tells us the y-intercept of the second line is -6.

so we plug the two knowns into slope intercept form to get the equation of the second line:

y = 3x - 6

I hope this helps and is the BRAINLIEST!

Great luck with your studies :)

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Customers arrivals at a checkout counter in a department store per hour have a Poisson distribution with parameter λ = 7. Calcul

IgorLugansk [536]

Answer:

(1)14.9% (2) 2.96% (3) 97.04%

Step-by-step explanation:

Formula for Poisson distribution: $P(k) = \frac{\lambda^ke^{-k}}{k!}$ where k is a number of guests coming in at a particular hour period.

(1) We can substitute k = 7 and $\lambda = 7$ into the formula:

$P(k=7) = \frac{7^7e^{-7}}{7!}$

$P(k=7) = \frac{823543*0.000911882}{5040} = 0.149 = 14.9\%$

(2)To calculate the probability of maximum 2 customers, we can add up the probability of 0, 1, and 2 customers coming in at a random hours

$P(k\leq2) = P(k=0)+P(k=1)+P(k=2)$

$P(k\leq2) = \frac{7^0e^{-7}}{0!} + \frac{7^1e^{-7}}{1!} + \frac{7^2e^{-7}}{2!}$

$P(k \leq 2) = \frac{0.000911882}{1} + \frac{7*0.000911882}{1} + \frac{49*0.000911882}{2}$

$P(k\leq2) = 0.000911882+0.006383174+0.022341108 \approx 0.0296=2.96\%$

(3) The probability of having at least 3 customers arriving at a random hour would be the probability of having more than 2 customers, which is the invert of probability of having no more than 2 customers. Therefore:

$P(k\geq 3) = P(k>2) = 1 - P(k\leq2) = 1 - 0.0296 = 0.9704 = 97.04\%$